This is the assumption method ;)
Take all tickets to be adult tickets
$9 x 553 = $4977
Then..... $4977 - $3936 = $1041
The difference between the child and adult ticket is $3, so divide $1041 by $3
$1041 divided by $3 = 347
347 is the number of <em>child </em>tickets sold
347 x $6 = $2082
So 553 - 347 = 206 ( no. of adult tickets )
206 x $9 = $1854
Child tickets sold : 347
Adult tickets sold : 206
:0 ITS MAGIC IM SO SMART
Answer:
The sum of a number and its additive inverse is equal to 0.
Step-by-step explanation:
Area of a rectangle is length * width
9.5*6=57
<u>ANSWER:</u>
The price of senior citizen ticket is $4 and price of child ticket is $7.
<u>SOLUTION:
</u>
Given, first day of sales the school sold 3 senior citizen tickets and 9 child tickets for a total of $75.
The school took in $67 on the second day by selling 8 senior citizen tickets and 5 child tickets.
We need to find what is the price each of one senior citizen tickets and one child tickets.
Let, the price of senior citizen ticket be "x" and price of child ticket be "y"
Then according to the given information,
3x + 9y = 75
x + 3y = 25 [by cancelling the common term 3.
x = 25 – 3y ---- (1)
And, 8x + 5y = 67 ---- (2)
Substitute (1) in (2)
8(25 – 3y) + 5y = 67
200 – 24y + 5y = 67
5y – 24y = 67 – 200
-19y = -133
y = 
y = 7
Now substitute y value in (1)
x = 25 – 3(7)
x = 25 – 21 = 4
Hence, the price of senior citizen ticket is $4 and price of child ticket is $7.
It’s not 3 or 4 so I think 2