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3 years ago

Solve the equation by finding the common multiple. (1 point)

Mathematics

2 answers:

Grace [21]3 years ago

6 0

Answer:

Three fifths minus one third plus nine fifteenths equals :---

$→(\frac{3}{5}-\frac{1}{3}+\frac{9}{15}) = \frac{(9 - 5 + 9)}{15}=\boxed{\frac{13}{15}}✓\\$

<h3><u>Thirteen fifteenths (=13/15)</u> is the right answer.</h3>

Natali5045456 [20]3 years ago

5 0

Answer:

nine fifteenths=1/3 fifteen thirteenths=1/1 eleven fifteenths=1/1 thirteen fifteenths=1/1

Step-by-step explanation:

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Answer:

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3 years ago

Write the resultant of the two vectors as an ordered pair. –6 5 and 6 –5

RideAnS [48]

Answer:

Resultant vector of two vectors is (0, 0).

Step-by-step explanation:

in this question two vectors having ordered pair (-6, 5) and (6, -5) have been given.

We can represent these vectors in the form of

$\vec{A}=-6\hat{x}+5\hat{y}$

and $\vec{A'}=6\hat{x}+(-5)\hat{y}$

Now the resultant of these vectors will be = A + A'

A + A' = $\vec{A}=-6\hat{x}+5\hat{y}$ + $\vec{A'}=6\hat{x}+(-5)\hat{y}$

So the resultant vector = (0 + 0)

Therefore the resultant will be (0, 0)

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Step-by-step explanation:

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2 years ago

What is the simplified form of the expression k^3(k7/5)^-5

saveliy_v [14]

The expression can be simplified as:

k^3(k7/5)^-5
= k^(3+-5) * (7/5)^-5
(Collecting the powers of k at one side and the constants at other side)
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(Solving thr integer powers)
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3 years ago