Answer:
x = number of bicycles = 35
y = number of cars = 55
Step-by-step explanation:
Let
x = number of bicycles
y = number of cars
x + y = 80 (1)
2x + 4y = 270 (2)
From (1)
x = 80 - y
Substitute x = 80 - y into (2)
2x + 4y = 270 (2)
2(80 - y) + 4y = 270
160 - 2y + 4y = 270
- 2y + 4y = 270 - 160
2y = 110
y = 110/2
y = 55
Substitute y = 55 into (1)
x + y = 80 (1)
x + 55 = 80
x = 80 - 55
x = 35
x = number of bicycles = 35
y = number of cars = 55
You would do 6.4/1.6 because big should come first or the number will change
Set two contains an outlier, which is 100
The measure of spread that was most impacted by the outlier is the range
This is because in set two, the median,both quartile and the interquartile range are all closely grouped together but the range is 93, which is far far away from any of those other values
Option A is right answer that is write a linear function that expresses the book value of the computer as the function of its age. (slop-intercept form)
