The answer is 3. I hope this helps!
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Answer:
ΔDCE by ASA
Step-by-step explanation:
The marks on the diagram show AE ≅ DE. We know vertical angles AEB and DEC are congruent, and we know alternate interior angles BAE and CDE are congruent. The congruent angles we have identified are on either end of the congruent segment, so the ASA theorem applies.
Matching corresponding vertices, we can declare ΔABE ≅ ΔDCE.
