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3 years ago

6

Help!!!!!!!!!!!!!!!!!!!!!!!!!!

1 answer:

ArbitrLikvidat [17]3 years ago

7 0

Answer and Step-by-step explanation:

0 to the power of 4 is 0.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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What is the value of the expression below when x = 3?<br> 10x2 – 7x + 10

QveST [7]

Answer:

79

Step-by-step explanation:

To find the value of $10x^2 – 7x + 10$ , when x = 3, simply plug in the value of x in the expression and solve as follows:

$10(3)^2 – 7(3) + 10$

$10(9) – 21 + 10$

$90 – 21 + 10$

$79$

The value of $10x^2 – 7x + 10$ , when x = 3, is 79

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3 years ago

Introduction to the Quadratic Formula

vredina [299]

Answer:

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3 years ago

Toll booths are used to collect money from drivers who use a particular road. On average, 45 cars pass through a particular toll

Free_Kalibri [48]

Answer:

skskaka

Step-by-step explanation:

T(h)=75(h+45)

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3 years ago

Mrs. Lane took a survey of the types of pants her students were wearing. She collected the data: jeans 14, shorts 9, and capris

astra-53 [7]

36%
14+9+2=25
9/25=.36

3 0

3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago