Ask question

Ask question

All categories

3 years ago

13

Matt saves 7 dollars every week in order to buy a guitar. Write an equation, using x for the independent variable and y for the

dependent variable. If he saved for 19 weeks, how much money did he save?

1 answer:

ANEK [815]3 years ago

5 0

Answer:

y = 7x

y = $133

Step-by-step explanation:

x = independent variable

y = dependent variable

y = 7x

Where,

y = total amount saved

x = number of weeks

7 = constant

When x = 19

y = 7x

y = 7 * 19

y = 133

y = $133

You might be interested in

Working simultaneously and independently at an identical constant rate, 4 machines of a certain type can produce a total of x un

Jobisdone [24]

Answer:

B. 18

Step-by-step explanation:

The 4 machines can produce x units in 6 days. This means they have a daily total rate of x/6 units per day.

Since the machines are similar and that they work at the same rate, this means that the individual rates of each machine would be x/6/4 = x/24 units per day.

Now we are looking at producing 3x units in 4 days. This means that we want to produce 3x/4 units in a single day. Now, since each machine would work at a rate of x/24, we need to know the number of machines we need. To know this number, we simply divide what is to be achieved by the individual rate:

This is 3x/4 divided by x/24. This mathematically means 3x/4 * 24/x = 18 machines

4 0

3 years ago

What’s the solution of x+4<8

aniked [119]

Answer:

x<4

Move all terms not containing x to the right side of the inequality.

7 0

3 years ago

Read 2 more answers

The Print Shop provides copying services to the general public. The Print Shop has equipment which is capable of making 1,800 co

steposvetlana [31]

a) The financial analysis determining the acceptance of the special order is as follows:

Data and Financial Analysis:

Capacity of photocopier per hour = 1,800 copies

Practical capacity of equipment = 7 hours

Total copies in a day = 12,600 (1,800 x 7)

Steady demand per day = 10,000

Variable cost per copy = $0.22

Service price per copy = $0.25

Profit per copy = $0.03 ($0.25 - $0.22)

Normal profit based on steady demand of 10,000 = $300 ($0.03 x 10,000)

Profit based on maximum capacity of 12,600 = $378 ($0.03 x 12,600)

Price per copy for the special customer = $0.24

Profit per copy based on special price of $0.24 = $0.02 ($0.24 - $0.22)

Profit from special customer with 5,000 pages = $100 (5,000 x $0.02)

Profit from other probable customers = $228 (7,600 x $0.03)

Lost profit for accepting special order based on maximum capacity = $50 ($378 - $228 - $100)

Lost profit if order is <u>not accepted</u> and demand is only 10,000 copies = $78 ($378 - $300)

Therefore, the special order at $0.24 should be accepted.

b) The largest order from customer that the shop could accept = 5,000 + $50/$0.02

= 5,000 + 2,500

= 7,500 copies

Thus, if the customer orders 7,500 copies to be made, the shop can still realize a maximum profit of $378 by accepting orders for additional 5,100 (12,600 - $7,500) copies from others.

Learn more: brainly.com/question/22599880

7 0

2 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

Masja [62]

Answer:

9

Step-by-step explanation:

By joining N to L, you will have a right angled triangle which is right angle at N. Then r^2+36=(3+x)^2. r=9/2. PQ=2r=9

8 0

3 years ago