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Aleksandr-060686 [28]
4 years ago
15

−5|x + 1| = 10 what is the answer to that

Mathematics
1 answer:
Dmitriy789 [7]4 years ago
6 0

Answer:

x = -3

Step-by-step explanation:

-5(x+1) = 10

Distribute

-5x - 5 = 10

get rid of the -5 by making it positive and adding it to the other side

-5x = 15

divide 15 by -5

x = -3

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A positive integer is 5more than 23 times another. Their product is 6732. Find the two integers
aliina [53]

One integer is m.

The other integer is n.


n = 23m + 5

mn = 6732


m = 6732/n


n = 23 * 6732/n + 5


n = 154,836/n + 5


n^2 = 154,836 + 5n


n^2 - 5n - 154,836 = 0


n = [5 +- sqrt(25 + 4 * 154,836)]/2


n = (5 +- 787)/2


n = 396 or n = -391


We discard -391 because the problem is looking for positive integers.


mn = 6732


m = 6732/n = 6732/396


m = 17


Answer: The integers are 17 and 396.

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3 years ago
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7 0
3 years ago
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Nat2105 [25]
1500ML=1.5 Liters
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7 0
3 years ago
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6 0
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The point (- square-root 2/2, square-root2/2 is the point at which the terminal ray of angle theta intersects the unit circle. W
Rufina [12.5K]

Answer: The value of cosine is \frac{-\sqrt{2}} {2} and the value of cotangent is -1.

Explanation:

The given point is (\frac{-\sqrt{2}} {2}},\frac{\sqrt{2}} {2}).

Since the x coordinate is negative and y coordinate is positive so the point must be lies in second quadrant.

The distance of the point from the origin is,

r=\sqrt{(\frac{-\sqrt{2}} {2}-0)^2+(\frac{\sqrt{2}} {2}-0)^2}

r=\sqrt{ \frac{2}{4}+\frac{2}{4}}

r=1

The given point is in the form of (a,b). So we get,

a=\frac{-\sqrt{2}} {2}

b=\frac{\sqrt{2}} {2}

The formula for cosine,

\cos \theta =\frac{a}{r}

\cos \theta =\frac{\frac{-\sqrt{2}} {2}}{1}}

\cos \theta =\frac{-\sqrt{2}} {2}}

The formula for cotangent,

\cot \theta =\frac{a}{b}

\cos \theta=\frac{\frac{-\sqrt{2}} {2}}{\frac{\sqrt{2}} {2}}

\cos \theta=-1

Therefore, the value of cosine is \frac{-\sqrt{2}} {2} and the value of cotangent is -1.

7 0
3 years ago
Read 2 more answers
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