The sum is composite because it is the same as multiplying the number by two.
The expression is
5x + 5y
We are to prove that it is an odd integer when x and y are integers of opposite parity
First, we can assume
x = 2a (even)
y = 2b + 1(odd)
subsituting
10(a + b) + 5
5 [(2(a + b) + 1]
The term
2(a + b) + 1 is odd and the result of an odd number multiplied by an odd number is odd
A) 5/2x^3-9/4x^2+7/2x-3/2
b) the ans. are not the same.
2-10 = -8 I'm not sure what the 5,6,7,8,9,10 means if you tell me i might be able to help you