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3 years ago

Faz um bom tempo que não faço expressões numéricas,vcs podem me ajudar!

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

6 0

Answer:

English Plz

Step-by-step explanation:

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1 year ago

How many groups of 1/2 days are in 1 week? Write a multiplication equation or a division equation to represent the question, the

worty [1.4K]

Answer:

14 groups

Step-by-step explanation:

Given

$Groupings = \frac{1}{2}\ day$

$Duration = 1\ week$

Required

Determine the number of group in the week

To do this, we simply divide the duration by the number half day group.

This gives:

$Group = \frac{Duration}{Groupings}$

$Group = \frac{1\ week}{1/2\ days}$

Convert week to days

$Group = \frac{7\ days}{1/2\ days}$

$Group = \frac{7}{1/2}$

$Group = 7 / \frac{1}{2}$

Convert to multiplication

$Group = 7 * \frac{2}{1}$

$Group = \frac{14}{1}$

$Group = 14$

<em>Hence, there are 14 groups</em>

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2 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

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3 years ago

Let f(x)=x2+2x+3 . What is the average rate of change for the quadratic function from x=−2 to x = 5? Enter your answer in the bo

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Answer:

Hello I just took the test and the answer is 5!

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2 years ago

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What percent of 74 is 13.6? Write your answer to the nearest tenth.

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Answer:

18.37 is the answer so it should be 18.4

Step-by-step explanation:

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