Answer:
a) 
b) 
c) 
d) 
Step-by-step explanation:
a) 
When factoring a binomial (a polynomial with two terms), what we will be looking for are the terms that are shared between them.
In this problem, it can be seen that both of these terms have and x. This means that we can factor it out to get

b) 
What are the common terms here?
It can be seen that each of these share a 2x, so our factored form would be

c) 
What about this one?
The common factor of this one is 5x, so our factored form would be

d) 
The common factor of this one is
, so our factored form would be

Answer:
Step-by-step explanation:
The constant of proportionality 'k' between two variables ( one independent and one dependent ) is given by :-

In the given table, independent variable = Days
Dependent variable = Total Miles
From first row, Days = 3
Total Miles = 
Then, the constant of proportionality in the table

Hence, the constant of proportionality in the table is
.
The perimeter of a rectangle is <u>length + length + width + width</u>.
We know that the length of a rectangle is 3cm more than its width, which gives us the equation: (l for length and w for width)
l = 3 + w
We also know that the perimeter of the rectangle is 98cm, which gives us the equation:
98 = 2l + 2w (equation for perimeter of a rectangle as noted above)
We can divide both sides of this equation by 2 to get:
49 = l + w
Now we'll stick l = 3 + w into the above equation, which gives us:
49 = 3 + w + w
which simplifies to 49 = 3 + 2w.
Now we'll subtract 3 from both sides:
49 - 3 = 46
3 + 2w - 3 = 2w
which gives us 46 = 2w.
Dividing both sides by 2 gives us 23 = w.
Substituting w = 23 into the equation l = 3 + w gives us:
l = 3 + 23
l = 26cm.
Let's check our answer. 26cm is 3cm more than 23cm. 26cm + 26cm + 23cm + 23cm gives us 98cm. The length is 26cm and the width is 23cm.
Answer:
(8, -8)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = x - 16
5y = 2x - 56
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in <em>y</em>: 5(x - 16) = 2x - 56
- Distribute 5: 5x - 80 = 2x - 56
- [Subtraction Property of Equality] Subtract 2x on both sides: 3x - 80 = -56
- [Addition Property of Equality] Add 80 on both sides: 3x = 24
- [Division Property of Equality] Divide 3 on both sides: x = 8
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = x - 16
- Substitute in <em>x</em>: y = 8 - 16
- Subtract: y = -8