Since the quadratic formula of ax^2+bx+c is
x=(-b+-(plus OR minus) sqrt (b^2-4ac))/2a, we can get that a is 1 (since 1*x^2 is x^2), b is 4, and c is -16, so x=(-4+-sqrt((-4)^2-4*1*(-16)))/2*1
= (-4+-sqrt(16-(-64)))/2=(-4+-sqrt(80))/2 which is either (-4+sqrt(80))/2 or
(-4-sqrt(80))/2. Since 80 is divisible by 4 (aka 2 squared), we can write sqrt(80) as 2*sqrt(20) as 4 goes into 80 20 times, getting (-4+2sqrt(20))/2 or
(4-2sqrt(20))/2, and crossing out the 2's we get (-2+sqrt(20)) or (-2-sqrt(20))
Answer: There isn't a possible way you can really answer this question because I don't know how much one piece cost in the first place , but if I had to guess I would say around 50-80 dollars for a cake is enough for 57 guests.
explanation: I say this because I know usually cakes for a decent amount of people are around 50-80 dollars.
Answer:
G(3, 1), H(2, 3)
Step-by-step explanation:
When D is the midpoint of EG, it means ...
D = (E + G)/2
or
G = 2D -E = 2(3,4) -(3,7) = (2·3-3, 2·4-7) = (3, 1)
Likewise, H is ...
H = 2D -F = 2(3,4) -(4,5) = (2·3-4, 2·4-5) = (2, 3)
Answer: x = 40
Step-by-step explanation:
4= x/-4 + 14 Remember that in front of every variable there is a number 1.
4 = - 1/4x + 14 subtract 14 from both sides
-14 -14
-10 = -1/4x Divide both sides by -1/4
x = 40