2 years ago

Find the perimeter and area of isosceles trapezoid EFGH. A=1/2(b1+b2)•h

Mathematics

1 answer:

vfiekz [6]2 years ago

7 0

We have a height of 4, bottom base of 8, top base of 6, so

A = (1/2)(8+6)(4) = 28

Perimeter, we have sides that are hypotenuses of a right triangle, legs 1 and 4,

s = √(1²+4²) = √17

So perimeter is

P = 8 + 6 + √17 + √17 = 14+ 2√17

Answer: Area 28, perimeter 14 + 2√17

You might be interested in

Sum one please help need answerssssss pleaseeeeee

erma4kov [3.2K]

Answer:

Step-by-step explanation:

look it up

3 0

2 years ago

How are the following three expressions different from each other, if indeed they are? do not just state the value of each but e

Lisa [10]

Answer:

Below.

Step-by-step explanation:

Number is different to the other 2. Its value is +4 because negative 2 squared = + 4.

The other 2 have negative values and -2 = -(2) so they have the same value, -4.

8 0

2 years ago

What is 8 thousandths less than 4.989?

emmainna [20.7K]

8000-4.989 so when you see the word less than it means that you have to subtract and more than you have to add so the answer for this question will be 7,995.011

8 0

2 years ago

I’ll be very grateful for anyone’s help I added a photo of the question

Irina18 [472]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Brainliest? :(

Svetlanka [38]

Answer:

$(f\cdot g)(x)=2x^2+10x+12$

$(f-g)(x)=-x-1$

$(f+g)(1)=10$

Step-by-step explanation:

$\tt f(x)=x+3$

$\tt g(x)=2x+4$

$(f\cdot g)(x)=f(x)\cdot g(x)=(x+3)(2x+4)=2x^2+4x+6x+12$

$=2x^2+10x+12$

$(f-g)(x)=f(x)-g(x)=x+3-(2x+4)=x+3-2x-4$

$=-x-1$

$(f+g)(1)=f(1)+g(1)=1+3+2(1)+4$

$=4+2+4=10$

7 0

2 years ago