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Vladimir79 [104]
3 years ago
15

NEED HELP GIVING BRAINLIEST

Mathematics
1 answer:
Pie3 years ago
4 0

For this case we have by definition, that the equation of a line in the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cutoff point with the y axis

We need two points through which the line passes to find the slope:

(0, -4)\\(1,0)

We found the slope:

m = \frac {y2-y1} {x2-x1}\\m = \frac {0 - (- 4)} {1-0} = \frac {4} {1} = 4

So, the equation is of the form:

y = 4x + b

We substitute a point to find "b":

-4 = 4 (0) + b\\-4 = b

Finally, the equation is:

y = 4x-4

Answer:

Option D

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Find the derivative of the function at P 0 in the direction of A. ​f(x,y,z) = 3 e^x cos(yz)​, P0 (0, 0, 0), A = - i + 2 j + 3k
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The derivative of f(x,y,z) at a point p_0=(x_0,y_0,z_0) in the direction of a vector \vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k is

\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}

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f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k

and

\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}

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3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}

3 0
4 years ago
Suppose that 8% of the general population has a disease and that the test for the diesease is accurate 70% of the time. What is
balu736 [363]

Answer:

P = 0.332

Step-by-step explanation:

The probability of having the disease is 0.08

The probability that the test predicts with accuracy is 0.7.

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Several cases may occur.

Case 1.

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Case 2

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Then the probability that the test predicts that you have the disease is the union of both probabilities P1 and P2

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x=10 people per large table.

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Your answer would be -14

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