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Murrr4er [49]
3 years ago
14

What is -6 and -4? find the distance between each pair of integers on a number line.

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
8 0
The answer will be 2
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Actual
Katena32 [7]

Answer:

Step-by-step explanation:

so first you multiply how much she jogged then put the in infront of the number

3 0
3 years ago
Factor this polynomial completely.<br> 6x2 + 7x - 20
Papessa [141]
It’s the third answer
(2x + 5) x ( 3x -4)
3 0
3 years ago
Simplify the expression.
raketka [301]
<span>
1/4 n (-24+8m-100p)
= -24n/4 + 8mn/4 - 100np/4
= -6n + 2mn - 25np

answer
</span>A. -6n + 2mn - 25np
5 0
3 years ago
Please explain the answer to 4367 ÷ 0.004
boyakko [2]
4367 ÷ 0.004 is 1091750. To solve this, you can use long division, by setting up the equation. Make sure to move the decimal. Then, divide the first digit, then the first two digits, and so on.
7 0
3 years ago
The harbormaster wants to place buoys where the river bottom is 20 feet below the surface of the water. Complete the absolute va
Natalija [7]

Answer:

The answer is below

Step-by-step explanation:

The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = ⅕ ⎜h − 240⎟ − 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet). A ship risks running aground if the bottom of its keel (its lowest point under the water) reaches down to the river bottom. Suppose you are the harbormaster and you want to place buoys where the river bottom is 20 feet below the surface. Complete the absolute value equation to find the horizontal distance from the left shore at which the buoys should be placed

Answer:

To solve the problem, the depth of the water would be equated to the position of the river bottom.

d(h)=river \ bottom\\\\The \ river \ bottom=-20\ feet(below)\\\\d(h) = -20\\\\\frac{1}{5}|h-240|-48=-20\\ \\\frac{1}{5}|h-240|=-20+48\\\\\frac{1}{5}|h-240|=28\\\\|h-240|=28*5\\\\|h-240|=140\\\\h-240=140\ or\ h-240=-140\\\\h=140+240\ or\ h=-140+240\\\\h=380\ or\ h=100\\\\The\ buoys\ should\ be\ placed\ at\ 100\ feet\ and\ 380\ feet\ from\ left-hand\ shore

4 0
3 years ago
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