Answer:
Carrots cost $ 1.75 a pound which is more than potatoes cost.
Step-by-step explanation:
Let,
Carrots cost $ x per pound and potatoes cost $ y per pound.
Buying 2 pounds of carrots and 3 pounds of potatoes will cost her
$ 
and
Buying 4 pounds of carrots and 4 pounds of potatoes will cost her
$ 
According to the question,
-----(1)
-----(2)
multiplying (1) by 2 we get,
-----(3)
Deducting (2) from (3) we get,
⇒ 
------------------(4)
Putting value of y in (1) we get,
⇒ 
------------(5)
Answer:
1st year is $75,000 * 0.04 = $3,000 $75,000+$3,000=$78,000
Step-by-step explanation:
Step-by-step explanation:
(b) If 
then
Note that 
cancel out so we get
Solving for 
we get
(c) I'm not sure what the problem is asking for but here goes. As r doubles, 
becomes
Both the general shape of a polynomial and its end behavior are heavily influenced by the term with the largest exponent. The most complex behavior will be near the origin, as all terms impact this behavior, but as the graph extends farther into positive and/or negative infinity, the behavior is almost totally defined by the first term. When sketching the general shape of a function, the most accurate method (if you cannot use a calculator) is to solve for some representative points (find y at x= 0, 1, 2, 5, 10, 20). If you connect the points with a smooth curve, you can make projections about where the graph is headed at either end.
End behavior is given by:
1. x^4. Terms with even exponents have endpoints at positive y ∞ for positive and negative x infinity.
2. -2x^2. The negative sign simply reflects x^2 over the x-axis, so the end behavior extends to negative y ∞ for positive and negative x ∞. The scalar, 2, does not impact this.
3. -x^5. Terms with odd exponents have endpoints in opposite directions, i.e. positive y ∞ for positive x ∞ and negative y ∞ for negative x ∞. Because of the negative sign, this specific graph is flipped over the x-axis and results in flipped directions for endpoints.
4. -x^2. Again, this would originally have both endpoints at positive y ∞ for positive and negative x ∞, but because of the negative sign, it is flipped to point towards negative y ∞.
