Answer:
We need a sample size of at least 170.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population(square root of the variance) and n is the size of the sample.
How large of a sample would be required in order to estimate the mean per capita income at the 80%80% level of confidence with an error of at most $0.52$ 0.52?
A sample size of at least n, in which n is found when 
So
Rounding up
We need a sample size of at least 170.
25 movies.
So basically you start and end at 1 month so,
Galore Cost =
$10
Galore Per Movie =
0.5 x 25 = 12.5 + 10 = $22,5
Cinephile Cost =
$15
Cinephile Per Movie =
0.25 x 25 = 6.25 + 15 = 21.25
These questions are just trial and error
Answer:
D,A
Step-by-step explanation:
N = 2424 is the sample size (amount of cars being sampled)
df = degrees of freedom
df = n-1
df = 2424-1
df = 2423
Side Note: if there is a typo and the sample size should be n = 24 (instead of 2424), then the df would be df = n-1=24-1 = 23
Answer:
Distribute or Die part 2: Attack of the PEMDAS!
