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Elden [556K]
3 years ago
11

$35.99 with a 5% sales tax

Mathematics
2 answers:
OLga [1]3 years ago
7 0
The price in total would be $38 
jolli1 [7]3 years ago
6 0
1.80 I think. It's actually 1.7995 but in money we round so it's 1.80
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Determine the equation of the graph with the coordinates of (4, -1)
Anon25 [30]

Answer:

The required equation of the graph with the coordinates of (4, -1) will be:

  • y=\left(x-4\right)^2-1

The graph is also attached.

Step-by-step explanation:

Given the coordinates (4, -1)

If we put the coordinate values (4, -1) in the given equations, we determine that only y=\left(x-4\right)^2-1 is the valid equation as it satisfies the given coordinate value.

For example, putting  (4, -1) in the equation

y=\left(x-4\right)^2-1

\left(-1\right)=\left(4-4\right)^2-1

-1=\left(0\right)^2-1

-1=0-1

-1=-1

So, the equation y=\left(x-4\right)^2-1 is true for the coordinate values (4, -1).

Therefore, the required equation of the graph with the coordinates of (4, -1) will be:

  • y=\left(x-4\right)^2-1

Please check, the graph is also attached.

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3 years ago
0.07 is one tenth of
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0.07 is one tenth of 0.7
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3 years ago
You have 12 shirts and plan to wear a different one each day from Monday
JulsSmile [24]
It should be 95,040. On the first day, you have 12 choices. On the second, eleven, and so on, until day 5. 12x11x10x9x8.
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Read 2 more answers
What kind of sequence has a common ratio
Makovka662 [10]

Answer:

geometric sequence

Step-by-step explanation:

A geometric sequence is a sequence of numbers that is ordered with a specific pattern. Each successive number is the product of the previous number and a constant. The constant is the same for every term in the sequence and is called the common ratio.

6 0
3 years ago
Can someone help me with this? I need to find the points of discontinuity/limits for each of these. I think one point is 4, but
Debora [2.8K]
The answers are shown in the attached image

-------------------------------------------------------------------------

Explanation:

Set the denominator x^4-8x^3+16x^2 equal to zero and solve for x

x^4-8x^3+16x^2 = 0
x^2(x^2-8x+16) = 0
x^2(x-4)^2 = 0
x^2 = 0 or (x-4)^2 = 0
x = 0 or x-4 = 0
x = 0 or x = 4

The x values 0 and 4 make the denominator zero

These x values lead to asymptote discontinuities because the numerator 8x-24 = 8(x-3) has no common factors which cancel with the denominator factors.

There are two vertical asymptotes

Let's see what happens when we plug in a value to the left of x = 0, say x = -1, we'd get
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(-1) = (8(-1)-24)/((-1)^4-8(-1)^3+16(-1)^2)
f(-1) = -1.28
So as x gets closer and closer to x = 0 from the left side, the f(x) is heading to negative infinity

Now plug in some value to the right of x = 0. I'm going to pick x = 1
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(1) = (8(1)-24)/((1)^4-8(1)^3+16(1)^2)
f(1) = -1.78 (approximate)
So as x gets closer and closer to x = 0 from the right side, the f(x) is heading to negative infinity

Overall, as x approaches 0 from either the left or right side of x = 0, the y value is heading off to negative infinity

---------------------

Repeat for values to the left and right of x = 4
We can't use x = 1 as it turns out that x = 3 is a root
But we can use something like x = 3.5 to find that...
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(3.5) = (8(3.5)-24)/((3.5)^4-8(3.5)^3+16(3.5)^2)
f(3.5) = 1.31 approx
So as x gets closer to x = 4 from the left, y is getting closer to positive infinity

Plug in x = 5 to find that
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(5) = (8(5)-24)/((5)^4-8(5)^3+16(5)^2)
f(5) = 0.64
which has the same behavior as the left side

So overall, as we approach x = 4, the y value is heading off to positive infinity

Again everything is summarized in the image attachment

Note: you could make a table of more values but they would effectively say what has already been said. It would be redundant busy work. However, its always good practice for function evaluation. 

6 0
3 years ago
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