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3 years ago

John does 96 pushups and 4 days how many pushups does he do in one day

Mathematics

2 answers:

Vsevolod [243]3 years ago

4 0

96 divided amongst 4 days, 96 divided by 4 is 24.

SVETLANKA909090 [29]3 years ago

3 0

This answer can be found by taking 96/4 (96 decided by 4), which is 24. John does 24 push ups per 1 day.

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How many solutions y= -2x -4 and y=3x plus 3

Oksi-84 [34.3K]

Answer:

The number of solutions is one

Step-by-step explanation:

Here, we want to get the number of solutions

since the linear equations are not the same, neither do they have the same x-variable, we can have only one solution

6 0

2 years ago

A punch glass is in the shape of a hemisphere with a radius of 5 cm. If the punch is being poured into the glass so that the cha

Galina-37 [17]

Answer:

28.27 cm/s

Step-by-step explanation:

Though Process:

The punch glass (call it bowl to have a shape in mind) is in the shape of a hemisphere
the radius $r=5cm$
Punch is being poured into the bowl
The height at which the punch is increasing in the bowl is $\frac{dh}{dt} = 1.5$
the exposed area is a circle, (since the bowl is a hemisphere)
the radius of this circle can be written as $'a'$

what is being asked is the rate of change of the exposed area when the height $h = 2 cm$
the rate of change of exposed area can be written as $\frac{dA}{dt}$ .
since the exposed area is changing with respect to the height of punch. We can use the chain rule: $\frac{dA}{dt} = \frac{dA}{dh} . \frac{dh}{dt}$

and since $A = \pi a^2$ the chain rule above can simplified to $\frac{da}{dt} = \frac{da}{dh} . \frac{dh}{dt}$ -- we can call this Eq(1)

Solution:

the area of the exposed circle is

$A =\pi a^2$

the rate of change of this area can be, (using chain rule)

$\frac{dA}{dt} = 2 \pi a \frac{da}{dt}$ we can call this Eq(2)

what we are really concerned about is how $a$ changes as the punch is being poured into the bowl i.e $\frac{da}{dh}$

So we need another formula: Using the property of hemispheres and pythagoras theorem, we can use:

$r = \frac{a^2 + h^2}{2h}$

and rearrage the formula so that a is the subject:

$a^2 = 2rh - h^2$

now we can derivate a with respect to h to get $\frac{da}{dh}$

$2a \frac{da}{dh} = 2r - 2h$

simplify

$\frac{da}{dh} = \frac{r-h}{a}$

we can put this in Eq(1) in place of $\frac{da}{dh}$

$\frac{da}{dt} = \frac{r-h}{a} . \frac{dh}{dt}$

and since we know $\frac{dh}{dt} = 1.5$

$\frac{da}{dt} = \frac{(r-h)(1.5)}{a}$

and now we use substitute this $\frac{da}{dt}$ . in Eq(2)

$\frac{dA}{dt} = 2 \pi a \frac{(r-h)(1.5)}{a}$

simplify,

$\frac{dA}{dt} = 3 \pi (r-h)$

This is the rate of change of area, this is being asked in the quesiton!

Finally, we can put our known values:

$r = 5cm$

$h = 2cm$ from the question

$\frac{dA}{dt} = 3 \pi (5-2)$

$\frac{dA}{dt} = 9 \pi cm/s// or//\frac{dA}{dt} = 28.27 cm/s$

5 0

2 years ago

1/10 of 400,000 is 10 times as much as?

mote1985 [20]

40,000 is the answer

5 0

3 years ago

The varsity soccer team has 20 players. Three of the players are trained to be goalies while the remaining 17 can play any posit

Vadim26 [7]

Answer:

The coach can choose a lineup of 11 players in 6,047,981,701,347 different ways.

Step-by-step explanation:

Since the varsity soccer team has 20 players, and three of the players are trained to be goalies while the remaining 17 can play any position, and only 11 players can be on the field at once, and the coach wants to make sure there is exactly one goalie on the field, to determine how many ways can the coach choose a lineup of 11 players if exactly 1 player must be a goalie the following calculation has to be made:

3 x 17 ^ 10 = X

3 x 2,015,993,900,449 = X

6,047,981,701,347 = X

Therefore, the coach can choose a lineup of 11 players in 6,047,981,701,347 different ways.

6 0

3 years ago

PLEASE HURRY I NEED HELP SOS!!!!!!!! (15 POINTS)

yaroslaw [1]

Answer:

0, π, 7π/6, 11π/6 on the interval 0 ≤ ø <2π.

Step-by-step explanation:

sinø + 1 = cos2ø

Use the identity cos 2o = 1 - 2 sin^2 o:

sin o + 1 = 1 - 2 sin^2 o

2sin^2 o + sin o + 1 - 1 = 0

2 sin^2 o + sin o = 0

sin o (2 sin 0 + 1) = 0

Therefore sin o = 0 or sin o = -1/2.

For sin o = 0 , o = 0, π radians.

For sin o = - 1/2, o = 7π/6, 11π/6 radians.

8 0

3 years ago