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3 years ago

15

An isosceles triangle has an angle that measures 90°. Which other angles could be in that isosceles triangle? Choose all that ap

ply.

1 answer:

Inga [223]3 years ago

8 0

Answer:

Step-by-step explanation:

If one angle = 90 degrees, then the other 2 added together must also = 90.

There is only 1 answer to this, since the triangle is isosceles..

x + x = 90 Combine

2x = 90 Divide by 2

x = 90/2

x = 45

So both acute angles = 45 degrees.

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Kelsey had $65 to spend on books. Each book cost $5.50, and there was a $7.50 fee for shipping. She let b equal the number of bo

larisa86 [58]

Kelsey must spend less than or equal to $65.
The expression 5.50b+7.5 is correct
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3 years ago

Read 2 more answers

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

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3 years ago

Can you please help me on this question 8(4-x)=7x+2

kati45 [8]

Answer:

2=x

Step-by-step explanation:

8(4-x)=7x+2

Distribute

32 - 8x = 7x+2

Add 8x to each side

32 - 8x+8x = 7x+8x+2

32 = 15x+2

Subtract 2 from each side

32-2 = 15x+2-2

30 = 15x

Divide each side by 15

30/15 = 15x/15

2 =x

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3 years ago

A right rectanular prism has a length of 2 a width of 4 and a height of 5. How many unit cubes can fit in the prism

-Dominant- [34]

Answer:

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Step-by-step explanation:

4 x 2 = 8 x 5

l x w x h

or

Bxh

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2 years ago

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Anit [1.1K]

Answer:

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3 years ago