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statuscvo [17]
2 years ago
15

An isosceles triangle has an angle that measures 90°. Which other angles could be in that isosceles triangle? Choose all that ap

ply.
Mathematics
1 answer:
Inga [223]2 years ago
8 0

Answer:

Step-by-step explanation:

If one angle = 90 degrees, then the other 2 added together must also = 90.

There is only 1 answer to this, since the triangle is isosceles..

x + x = 90        Combine

2x = 90            Divide by 2

x = 90/2          

x = 45

So both acute angles = 45 degrees.  

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If (-5x^5) (a) = 25x^7 + 100x^5, find a
sweet-ann [11.9K]
(-5x^5)(a) = 25x^7 + 100x^5
<u>+5x^5                         +5x^5</u>
             a = 25x^7

4 0
3 years ago
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expeople1 [14]

Answer: 9


Step-by-step explanation:

To square a number, you multiply it by itself twice.

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Hope it helps! :)

3 0
3 years ago
Help me plz...
cestrela7 [59]

The 3 inside angles of a triangle need to add up to 180 degrees.

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A = 180 - 104 - 36 - 40

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4 0
3 years ago
Read 2 more answers
Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2
Ipatiy [6.2K]

Answer:

\frac{dAB}{dt}=340 mil/h

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here.  We can use the Pythagorean theorem, so the distance between the planes will be:

AB^{2} =AO^{2}+BO^{2} (1)

AB =\sqrt{AO^{2}+BO^{2}}=

AB =\sqrt{90^{2}+120^{2}}=150 miles

If we take the derivative of the equation (1) we could find the change of the distance between planes.

2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}

2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h

\frac{dAB}{dt}=\frac{102000}{150*2}

Finally,

\frac{dAB}{dt}=340 mil/h

I hope it helps you!

6 0
3 years ago
Can someone please help me with these math problems ​
yuradex [85]

Answer: 138

Step-by-step explanation:

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3 years ago
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