What are the points of intersections of the function g(x)=x+1

23 096 145

Yuri [45]

Answer:

twenty three million ninety six thousand one hundered fourty five

Step-by-step explanation:

not needed

4 0

1 year ago

What are the solutions to the equation

frosja888 [35]

Answer:

C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

3 0

2 years ago

Which rational exponent represents a square root?<br> A. 1 / 2<br> B. 3/2<br> C. 1/3<br> D. 1/4

Fofino [41]

Answer:

1/2 rational exponent represents a square root.

Therefore, option A is correct.

Step-by-step explanation:

As we know that raising to the one-half power i.e. $\frac{1}{2}$ is the same

as taking the square root.

so $x^{\frac{1}{2}}$ is the same as the square root of $x$ .

For example, taking the square root of 4 will determine:

$4^{\frac{1}{2}}$

$\mathrm{Factor\:the\:number:\:}\:4=2^2$

$4^{\frac{1}{2}}=\left(2^2\right)^{\frac{1}{2}}$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0$

$\left(2^2\right)^{\frac{1}{2}}=2^{2\cdot \frac{1}{2}}$

so the expression becomes

$4^{\frac{1}{2}}=2^{2\cdot \:\frac{1}{2}}$

$=2^1$

$=2$ ∵ $\mathrm{Apply\:exponent\:rule}:\quad \:a^1=a$

so, 1/2 rational exponent represents a square root.

Therefore, option A is correct.

5 0

2 years ago

Read 2 more answers

Please answer these two questions.

Umnica [9.8K]

I think 6) is 17/25, 82%, 8,5, 8/5

6 0

2 years ago

Read 2 more answers

Taxi A charges $0.20 per mile and an initial fee of $4. Taxi B charges $0.40 per mile and an initial fee of $2. Write an inequal

Paraphin [41]

Well, for taxi A we have:

Cost of Taxi A = $ 0.20*X + $4
With "X" equal to "miles traveled".
For taxi B we have:
Cost of Taxi B = $ 0.40*X + $2
Then, when
Cost of Taxi B > Cost of Taxi A,

We Have:
$ 0.40*X + $2 > $ 0.20*X + $4

That is the inequality that you need!
Good luck!
M.

7 0

3 years ago