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4 years ago

Can someone answer this please so I can go to the back page

Mathematics

1 answer:

igomit [66]4 years ago

7 0

Blake has 25 CD's.

25 times 3 = 75
75 + 7 = 82

Joel has 82 CD's.

If Joel has twice as many as Mariella, then divide 82 by 2 and you get 41.

Mariella has 41 CD's.

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Twice a number m minus three equals the sum of m and five

Leya [2.2K]

2m - 3 = m + 5

m = 8

2(8) - 3 = 13

(8) + 5 = 13

m = 8

8 0

3 years ago

In a recipe for pizza sauce, the ratio of cans of tomatoes to teaspoons of oregano is 1:6. How many teaspoons of oregano do you

irina1246 [14]

Answer:

48 teaspoons of Oregano

Step-by-step explanation:

Ratio is given as:

Cans of tomatoes : Teaspoons of Oregano

1 : 6

Hence:

1 can of tomatoes = 6 teaspoons of Oregano

8 can of tomatoes = x teaspoons

Cross Multiply

x = 8 × 6 teaspoons

x = 48 teaspoons of Oregano

3 0

3 years ago

jane can do a job in 3 hours, while gary can do the same job in 2 hours. if jane works alone for an hour before gary helps her h

Rudiy27

Answer: 2hrs?

Step-by-step explanation: 3-2=1+1 hour she took alone = 2hrs

8 0

2 years ago

Read 2 more answers

A cyclist travels at distance of 400 meters in 120 seconds towards school, calculate his speed. (Show your work)

DochEvi [55]

we know that

The scalar magnitude of the velocity vector is the speed. The speed is equal to

$Speed=\frac{distance}{time}$

in this problem we have

$distance=400\ m \\time=120\ sec$

substitute in the formula

$Speed=\frac{400}{120}$

$Speed=3.5\frac{m}{sec}$

therefore

the answer Part a) is

the speed is equal to $3.5\frac{m}{sec}$

Part b) Find the velocity

we know that

Velocity is a vector quantity; both magnitude and direction are needed to define it

in this problem we have

the magnitude is equal to the speed

$magnitude=3.5\frac{m}{sec}$

$direction=North\ East\ (NE)$

therefore

the answer Part b) is

the velocity is $3.5\frac{m}{sec}\ North\ East\ (NE)$

Part c)

we know that

the acceleration is equal to the formula

$a=\frac{V2-V1}{t2-t1}$

in this problem we have

$V2=0 \\V1=3.5\frac{m}{sec}$

$t2=15\ sec\\t1=0$

substitute in the formula

$a=\frac{0-3.5}{15-0}$

$a=-\frac{3.5}{15}\frac{m}{sec^{2}}$

$a=-\frac{7}{30}\frac{m}{sec^{2}}$

therefore

the answer Part c) is

the acceleration is $-\frac{7}{30}\frac{m}{sec^{2}}$

This is an example of negative acceleration

7 0

3 years ago

Read 2 more answers

Evaluate please I need helppppp

IrinaK [193]

Answer:

-5 sorry if it's wrong. I tried.

5 0

3 years ago

Read 2 more answers