The first coefficient is 2 and the last term is 6. They multiply to 2*6 = 12.
Now we must find two factors of 12 that add to 7 (the middle coefficient).
Through trial and error, you should find that:
3*4 = 12
3+4 = 7
So 3 and 4 are the numbers we're after. We'll split the 7m into 3m+4m and use the factor by grouping method as shown in the steps below.
2m^2 + 7m + 6
2m^2 + 3m + 4m + 6
(2m^2 + 3m) + (4m + 6)
m(2m + 3) + 2(2m + 3)
(m + 2)(2m + 3)
(2m + 3)(m + 2)
The order of the factors doesn't matter since something like 2*3 is the same as 3*2.
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Verifying the answer:
You can use technology like you did to check the answer, but here's one way to do it without a calculator.
(2m + 3)(m + 2)
n(m + 2) ...... let n = 2m+3
mn + 2n .... distribute
m( n ) + 2( n )
m(2m+3) + 2(2m+3) .... plug in n = 2m+3
m*2m + m*3 + 2*2m + 2*3 .... distribute
2m^2 + 3m + 4m + 6
2m^2 + 7m + 6
We arrive back at the original trinomial, so we have confirmed the answer.
F(3)=-18
You just replace x for three for your equation and then use Ofer of operations to solve it.
So f(3)= 21+ 2(3)-5(3)^2
The exponent goes first: f(3)= 21+ 2(3)-5(9)
Next is multiplication: f(3)= 21+ 6-45
Now add: f(3)= 27-45
Finally subtract: f(3)= -18
Hope this helps!
Answer:
I think it’s B
Step-by-step explanation:
I hope I helped
100 because of the system
have a good day
Answer:
Step-by-step explanation:
Given that :
μ1 = 39420 ; σ1 = 1659 ; s1 = 12
μ2 = 30215 ; σ2 = 4116 ; s2 = 26
df1 = 12 - 1 = 11
df2 = 26 - 1 = 25
98 % confidence interval of the difference in sample means :
Pooled Variance :
S²p = ((df1 * s1²) + (df2 * s2²)) / (df1 + df2)
((11×1659^2)+(25×4116^2))÷(11+25) = 12605874.75
Standard Error :
√(S²p/n1) + (S²p/n2)
√(12605874.75/12) + (12605874.75/26)
= 1239.0847
