Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

For parts (a) and (b), you're given everything you need to determine

.
For part (c), if

and

are mutually exclusive, then

, so

. If the given probability is

, then you can find

. But if this given probability is for the intersection, finding

is impossible.
For part (d), if

and

are independent, then

.
How many time that 6688 could into 16 which is 418
Answer:
100
Step-by-step explanation:
possibility of getting 6 in one roll = 1/6
Possibility of getting 6 in 600 rolls = 1/ 6 x 600 = 100
I hope im right!!!
I think it's $21.75 with tax
Step-by-step explanation:



HOPE IT HELPS Y