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slava [35]
2 years ago
9

Need help please hurry

Mathematics
2 answers:
Fofino [41]2 years ago
8 0
1. y=x•7
2.y=x•9
3.y=x•13
4. x=y•10
5.y=5x+1
6. y=4x+5
ella [17]2 years ago
5 0

1: Y=X•7

2:Y=X•9

3:Y=X•13

4Y=X÷10

5Y=X•5+1

6I Don't Know

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The tides are meaured at a forth D. The mean of the low tide values at Locations A,B C, and D,s is -0.54. What is the value of t
MAVERICK [17]
A - Difference in tides for location C is 6.9 feet and high tide for location A is 8.2 feet.
B - Value of low tide in location D is -0.64 feet.

The table showing the difference between high and low tides.
The difference in tides for location C = 7.34 - 0.44 = 6.9

We are given, the mean of the low tides for the 4 locations is -0.54
3 0
3 years ago
Is (6, 6) a solution to the equation y = x?
Andre45 [30]

Hey there! I'm happy to help!

This is a solution because x has the same value as y. They are both 6.

I hope that this helps! Have a wonderful day! :D

3 0
4 years ago
Read 2 more answers
Review of Significant Figures: How many significant figures does the result of the following calculation have: 24.78*(37.3-31.72
horsena [70]

Answer:

The significant figure of the result is 138.8

Step-by-step explanation:

24.78*(37.3 - 31.72)

Solving the bracket first:

37.3 - 31.72 = 5.58

A zero is added to 37.3 before the substraction, so;

37.3 - 31.72 = 37.30 - 31.72 = 5.58

Following the rule of significant figure; we have the answer of the substraction as 5.6 since the least number of significant is one decimal place.

The new expression will be:

24.78 * 5.6 = 138.768

Therefore, the result of our expression 138.8 by following the rule of significant figure

5 0
3 years ago
The answer to this question
WINSTONCH [101]

Answer:

d

Step-by-step explanation:

7 0
3 years ago
The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM. If 188 sixth graders
Anna007 [38]

Answer:

0.1836 = 18.36% probability that the sample mean would differ from the population mean by greater than 1.46 WPM

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM.

This means that \mu = 84, \sigma = 15

Sample of 188

This means that n = 188, s = \frac{15}{\sqrt{188}}

What is the probability that the sample mean would differ from the population mean by greater than 1.46 WPM?

Greater than 84 + 1.46 = 85.46 or less than 84 - 1.46 = 82.54. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Probability is is less than 82.54.

P-value of Z when X = 82.54. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{82.54 - 84}{\frac{15}{\sqrt{188}}}

Z = -1.33

Z = -1.33 has a p-value of 0.0918

2*0.0918 = 0.1836

0.1836 = 18.36% probability that the sample mean would differ from the population mean by greater than 1.46 WPM

3 0
3 years ago
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