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2 years ago

Need help please hurry

Mathematics

2 answers:

Fofino [41]2 years ago

8 0

1. y=x•7
2.y=x•9
3.y=x•13
4. x=y•10
5.y=5x+1
6. y=4x+5

ella [17]2 years ago

5 0

1: Y=X•7

2:Y=X•9

3:Y=X•13

4Y=X÷10

5Y=X•5+1

6I Don't Know

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Ecuaciones con resultado 17

babymother [125]

Answer:

x-1= -18

x = -18 +1

x = -17

2x - 4 = - 38

2x = -38 + 4

2x = -34

x = -34/2

x = -17

Step-by-step explanation:

6 0

3 years ago

What is the area of a regular 16-gon with a radius of 15 feet? Round your answer to the nearest tenth.

Sedbober [7]

Split up the 16-gon into 16 congruent isosceles triangles. Cut each of these isosceles triangles in half to get a right triangle.

The radius of the 16-gon corresponds to the hypotenuse of any of these 32 right triangles. As you probably know, the area of a triangle is half the product of its base and height. For a right triangle, the base and height can be taken to be the two legs. So you need to find their lengths.

Recall that the exterior angles of any convex polygon sum to 360º in measure. For a regular polygon, these angles are all congruent. There are 16 of them in this case, so they each have measure (360/16)º = 22.5º.

Interior angles are supplementary to exterior angles, which means each interior angle of the 16-gon has measure (180 - 22.5)º = 157.5º.

When we split up the 16-gon into isosceles triangles, the "base angles" are equal in measure to half the measure of the interior angles, since each hypotenuse bisects the interior angle. So each base angle has measure 78.75º.

In each right triangle, we then have base b and height h such that

sin(78.75º) = h/15

cos(78.75º) = b/15

Solve for h and b to get

b = 15 cos(78.75º)

h = 15 sin(78.75º)

Then the area of each right triangle is

1/2 b h = 225/2 sin(78.75º) cos(78.75º) = 225/4 sin(157.5º)

and so the area of the 16-gon is

32(1/2 b h) = 1800 sin(157.5º) ≈ 688.8 sq. ft.

4 0

4 years ago

Evaluate the surface integral. S xz ds, s is the part of the plane 2x 2y z = 4 that lies in the first octant

maksim [4K]

The value of the given surface integral is 4.

The given plane intercepts the coordinate axes at (2, 0, 0), (0, 2, 0), and (4, 0, 0). These point are the coordinates of a triangular region that we can parameterize using.

$S(u,v)=(1-u)((1-u)(2,0,0)+u(0,2,0)+u(4,0,0)\\S(u,v)=(2(1-u)(1-v),2u(1-v),4v)$

<h3>What is the surface integral?</h3>

A surface integral is a generalization of multiple integrals to integration over surfaces. It can be thought of as the double integral analog of the line integral. Given a surface, one may integrate a scalar field over the surface or a vector field.

with 0≤u≤1 and 0≤v≤1. Then the surface element ds is equivalent to

$ds=\||\:\left(s_u\times \:\:S_v\right)||dudv=12\left(1-v\right)dudv$

The surface integral is then

$\int \:\int \:_Sxzds=12\int _0^1\:\int _0^1\:\left(2\left(1-u\right)\left(1-v\right),2u\left(1-v\right),4v\right)dvdu=4$

Therefore the value of the given surface integral is 4.

To learn more about the integral visit:

brainly.com/question/14295614

#SPJ2

6 0

2 years ago

Find the points of Intersection of these graphs

geniusboy [140]

Answer:

the line crosses the parabola at (-2,4) and (3,9)

Step-by-step explanation:

y=x^2

y=x+6

set them equal to each other

x^2=x+6, now set it equal to zero

x^2-x-6=0, now find the root

(x+2)(x-3)=0, the x=-2, and x=3; now substitute into any of the equation to find the points where graphs intercept

at x= -2, y=(-2)^2=4, so one point is (-2,4)

at x=3, y=(3)^2=9, so other point is (3,9)

the line crosses the parabola at (-2,4) and (3,9)

8 0

3 years ago

What is the value of this expression 14−3? 164 112 12 64

Firlakuza [10]

Answer:

Step-by-step explanation:

14-3 = 11

you have 14 apples and you eat 3 of them. wow! now you have 11 apples!

4 0

3 years ago