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Ilia_Sergeevich [38]
3 years ago
8

19. GEOMETRY CONNECTION

Mathematics
1 answer:
Paul [167]3 years ago
6 0
The cylinder is 7.0771 centimeters tall

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Can anyone help me please?
kow [346]
12inches because 3 is pi and 2 is Radius so 3x2squared=12
3 0
3 years ago
Read 2 more answers
Use the diagram to fill in the blanks<br> x=<br> m∠=
faust18 [17]

Answer:

x = 21, m∠A = 23°, the measure of angle in the right = 67°

Step-by-step explanation:

The angles of a triangle sum up to 180°.

Right angles equals to 90°.

Thus, (2x - 19)° + (3x + 4)° + 90° = 180°

=> 5x + 75 = 180

=> 5x = 105

=> x = 21

m∠A=> 2(21) -19 = 23°

the measure of angle in the right=> 3(21) + 4 = 67°

8 0
2 years ago
Write an equation of the perpendicular bisector of the segment with end points M(1,5) and N(7,-1)
vitfil [10]
The perpendicular bisector of the segment passes through the midpoint of this segment. Thus, we will initially find the midpoint P:

P=\dfrac{(1,5)+(7,-1)}{2}=\dfrac{(8,4)}{2}=(4,2)

Now, we will calculate the slope of the segment support line (r). After this, we will use the fact that the perpendicular bisector (p) is perpendicular to r:

m_r=\dfrac{\Delta y}{\Delta x}=\dfrac{5-(-1)}{1-7}=\dfrac{6}{-6}\iff m_r=-1


p\perp r\Longrightarrow m_p\cdot m_r=-1\Longrightarrow m_p\cdot(-1)=-1\iff m_p=1

We can calculate the equation of p by using its slope and its point P:

y-y_P=m_p(x-x_P)\\\\&#10;y-2=1\cdot(x-4)\\\\&#10;y-2=x-4\\\\&#10;\boxed{p:~~y=x-2}
4 0
3 years ago
Mr. Sands drove 15 miles to the airport. When he was 3/5 of the way, he stopped for gasoline. How far did Mr. Sands drive before
irinina [24]

Answer:

9 miles

Step-by-step explanation:

15/5=3

so 3x3= 9 miles

3 0
3 years ago
Help me pls i need this
Marina CMI [18]

<em>so</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>2</em><em>8</em><em> </em><em>hours</em><em>.</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

8 0
3 years ago
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