What we are expected to solve for that the problem did not expressly state is most likely the number of hours that you could ride for an amount of $65.

firstly we need to model the inequality (equation) for this scenario.

the constant fee= $3 additional fee for helmet

$3+15n\leq 65\\\\$

We can now solve for n since the above inequality satisfies the condition presented in the problem statement.

$3+15n\leq 65\\\\15n\leq65-3\\\\ 15n\leq 62$

Divide both sides by 15 to find n

$n\leq 62/15\\\\n\leq 4hrs -8min$

8 0

3 years ago

A) 7.7 ft<br> b) 13.4 ft<br> c) 10.3 ft<br> d) 12.3 ft

ELEN [110]

Answer:

D. 12.3 ft

Step-by-step explanation:

This problem requires the use of trigonometric ratios. This one specifically uses the cosine ratio as it provides the hypotenuse and is asking for the side that is adjacent to the angle.

cos(40°)=a/16

cos(40°)×16=a/16×16

cos(40°)×16=a

a=12.256 ft

The length of side a is D. 12.3 ft.

3 0

3 years ago

Here's the question: You have an electrical circuit with various components, all of which are in series. The current (I) through

vredina [299]

Answer:Magnitude of voltage is 41.9963 volts

Step-by-step explanation:

Given that current I =5.772-5.323i mA

and impedance, Z=3.342+4.176i kilo ohms

Then voltage in the circuit = IZ

$=(5.772-5.323i)X10^{-3}X(3.342+4.176i)X10^{3}$

$V=(5.772-5.323i)X(3.342+4.176i)$

$V=19.290024+24.103872i-17.789466i-23..5148848i^{2}$

$V=41.518892+6.314406i$

Magnitude of V = $\sqrt{41.518892^{2} +6.314406^{2} }=\sqrt{1763.6901}=41.9963volts$

7 0

3 years ago

Please help ❗️❗️❗️❗️ Please! I will reward brainly

zhuklara [117]

Hey there :)

We know the distance formula is:
D = $\sqrt{(x2-x1)^2+(y2-y1)^2}$

1) Coordinates are: ( -10, -5 ) , ( 8 , 5 )
↓ ↓ ↓   ↓
x₁ y₁ x₂ y₂
We plug in the values
D = $\sqrt{(8 -(-10))^2+(5-(-5))^2}$
  ≈20.59 ≈ 20.6 (nearest tenth)

We do the same for the rest

2) Coordinates are ( 10 , 0 ) , ( -2 , 1 )
D = $\sqrt{(-2-10)^2+(1-0)^2}$
≈ 12.04 ≈ 12.0 (nearest tenth)

3) Coordinates are ( 4 , 8 ) , ( 7 , -8 )
D = $\sqrt{((7-4)^2+(-8-8)^2}$
≈ 16.27 ≈ 16.3 (nearest tenth)

4) Coordinates are ( -10, -4 ) , ( 8 , 8 )
D = $\sqrt{(8-(-10))^2+(8-(-4))^2}$
  ≈ 21.6 (nearest tenth)

5) Coordinates are ( 6 , -3 ) , ( -8 , 9 )
D = $\sqrt{(-8-6)^2 + (9-(-3))^2}$
≈ 18.4 (nearest tenth)

You can find the matching below :)

8 0

3 years ago