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3 years ago

Which binomial is a factor of the following quadratic? K2-12k+36

Mathematics

2 answers:

serg [7]3 years ago

6 0

K-6 is the answer because the factor

Nitella [24]3 years ago

5 0

9514 1404 393

Answer:

(k -6)

Step-by-step explanation:

The given quadratic is a perfect square, so has one repeated binomial factor:

k^2 -12k +36 = (k -6)^2

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X is a normally Distributed random variable with a standard deviation of 4.00. Find the mean of X when 64.8% of the area lies to

Cerrena [4.2K]

Answer:

Step-by-step explanation:

σ = 4 ; μ =?

8.52 to the left of X

P(X < 8.52) = 64.8%

P(X < 8.52) = 0.648

Using the Z relation :

(x - μ) / σ

P(Z < (8.52 - μ) / 4)) = 0.648

The Z value of 0.648 of the lower tail is equal to 0.38 (Z probability calculator)

Z = 8.52 - μ / 4

0.38 = 8.52 - μ / 4

0.38 * 4 = 8.52 - μ

1.52 = 8.52 - μ

μ = 8.52 - 1.52

μ = 7

5 0

3 years ago

The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar

Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

$\bar x$ represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=10-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical values.

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

$\chi^2_{\alpha/2}=19.022$

$\chi^2_{1- \alpha/2}=2.700$

And replacing into the formula for the interval we got:

$\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}$

$10.892 \leq \sigma^2 \leq 76.736$

Now we just take square root on both sides of the interval and we got:

$3.30 \leq \sigma \leq 8.76$

So the best option would be:

3.30<σ<8.76

7 0

2 years ago

A particular fruit's weights are normally distributed, with a mean of 618 grams and a standard deviation of 24 grams. If you pic

Lorico [155]

Answer: The probability is 0.5136.

To find this probability we have to find the range of the values on the normal distribution table.

First, we need to find the percent for each making z-score.

Lower end: 50/24 = 2.08 = 0.0183

Upper end: 2/24 = 0.08 = 0.5319

Now, that we have the upper and lower ends, we can subtract them to find the difference or the range.

0.5319 - 0.0183 = 0.5136

There is a 51.36% chance they are in the given range.

3 0

2 years ago

Write the linear equation in slope-intercept form

dolphi86 [110]

The y intercept is 0, and the slope is 5x.

Equation: y = 5x +0.

7 0

3 years ago

Question 1 (1 point)

olya-2409 [2.1K]

For this case we can propose a system of equations:

x: Let the variable that represents the number of small cookies