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mrs_skeptik [129]
3 years ago
11

What is the prime factorization of 693​

Mathematics
1 answer:
Inessa05 [86]3 years ago
5 0

Answer:

The prime factors of 693 are 3, 7, 11.

Hope this helps!

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A sundae requires 3 ice-cream scoops and 4 strawberries, and a milkshake requires 2 ice-cream scoops and 6 strawberries. Ramses
drek231 [11]

Answer:

System of inequalities:

3x+2y \leq 25 , 4x+6y \leq 37      

1) Maximum number of sundaes possible = 9

2) Maximum number of milkshakes possible = 6

3) Combination that uses the most of both Ice-cream and Strawberries = 7 scoop of ice-cream and 1 scoop of strawberries.

Step-by-step explanation:

Given : A sundae requires 3 ice-cream scoops and 4 strawberries, and a milkshake requires 2 ice-cream scoops and 6 strawberries.

Ramses wants to make sundaes and milkshakes with at most 25 ice-cream scoops and 37 strawberries.

Let x denote the number of sundaes he makes and y the number of milkshakes he makes.

First we represent in tabular form,

                             Sundae(x)            Milkshake(y)           Total

Ice-cream                  3                           2                         3x+2y

Strawberries             4                            6                         4x+6y

→System of inequalities:

Sundaes and milkshake with at most 25 ice-cream scoops=  3x+2y \leq 25

Sundaes and milkshakes with at most 37 strawberries = 4x+6y \leq 37      

→ Plotting the equations in the graph (figure attached)

1) Maximum number of sundaes possible:

Maximum no. of sundaes possible when y=0

From the graph y=0 at x=9.25

Therefore, Maximum number of sundaes possible is 9

2) Maximum number of milkshakes possible:

Maximum no. of milkshakes  possible when x=0

From the graph x=0 at y= 6.167

Therefore, Maximum number of milkshakes possible is 6

3) Combination that uses the most of both Ice-cream and Strawberries:

Combination of both is possible there is a intersection of both the equation

From the graph intersection point is x=7.6 and y=1.1

Therefore,  Combination that uses the most of both Ice-cream and Strawberries = 7 scoop of ice-cream and 1 scoop of strawberries.


5 0
4 years ago
What is the answer? To this question
Sauron [17]
So first divide 420 by 3 which gets you 140 so now you need to divide that 140 by 20 which is 7 so the jeweler could make 7 necklaces which is B. If you have any questions just ask. Hope I helped you ❤️
6 0
4 years ago
How many extraneous solutions does the equation below have?
FrozenT [24]

<u>Answer</u>

0


<u>Explanation</u>

(2m)/(2m+3)-(2m)/(2m-3)=1

Simplifying the left hand first

(2m)/(2m+3)-(2m)/(2m-3) = {2m(2m-3) - 2m(2m+3)}/(4m²-9)

                                        (4m²-6m-4m²-6m)/(4m²-9)

                                         = (-12m) / (4m²-9)

Now this equet to 1

(-12m) / (4m²-9) = 1

-12m =  4m²-9

4m²+ 12m -9 =0 ⇒⇒⇒ This is a quadratic equation that has 2 real solutions.

4m²+ 12m -9 =0

m² + 3m + (3/2)²= 9/4 + 9/4

(m + 3/2)² = 18/4

m = √18/2 - 3/2                or m = -√18/2 - 3/2

    = 0.621                                       = -3.621

So we can say that the equation has NO extraneous solutions.

Answer = 0

8 0
3 years ago
Read 2 more answers
Solve the equation. −4(−6)=12
nalin [4]

Answer:

24=12 or false

Step-by-step explanation:

6 0
3 years ago
Solve for y. 4y+5/3 = y-8/2 y = -4 y = -5 y = -8
horrorfan [7]

Answer:

<h3>y = -34/5</h3>

Step-by-step explanation:

\dfrac{4y+5}{3}=\dfrac{y-8}{2}\qquad\text{multiply both sides by }\ 2\cdot3=6\\\\6\!\!\!\!\diagup^2\cdot\dfrac{4y+5}{\not3_1}=6\!\!\!\!\diagup^3\cdot\dfrac{y-8}{\not2_1}\\\\2(4y+5)=3(y-8)\qquad\text{use distributive property}\\\\(2)(4y)+(2)(5)=(3)(y)+(3)(-8)\\\\8y+10=3y-24\qquad\text{subtract 10 from both sides}\\\\8y=3y-34\qquad\text{subtract 3y from both sides}\\\\5y=-34\qquad\text{divide both sides by 5}\\\\\boxed{y=-\dfrac{34}{5}}

5 0
3 years ago
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