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mrs_skeptik [129]
3 years ago
11

What is the prime factorization of 693​

Mathematics
1 answer:
Inessa05 [86]3 years ago
5 0

Answer:

The prime factors of 693 are 3, 7, 11.

Hope this helps!

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Spiral Review Hayden is attending a craft show. The cost of an admission ticket is $8. The cost of a raffle ticket for a handmad
LekaFEV [45]

Answer:

7

Step-by-step explanation:

$45- $8 = 37 (aka his raffle ticket spending money)

37÷5= 7, so the max # of raffle tickets he can buy is 7.

7 0
3 years ago
There is a bag filled with 3 blue and 4 red marbles. A marble is taken at random from the bag, the colour is noted and then it i
Morgarella [4.7K]

altogether there are 7 marbles in the bag.

put the marbles in fractions, so blue would be 3/7

and red would be 4/7. but becuase you need 2 of the same, you do

3/7 x 3/7 = 9/49

4/7 x 4/7 = 16/49

then add them togther

25/49

if you need it as a percentage, it is

51.020408163265%

8 0
3 years ago
From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
2 years ago
7 + X = 2x - 5<br> 7<br> Solve<br> 3
Anna11 [10]

Answer:

x=12

Step-by-step explanation:

7+x=2x-5

12=1x

x=12

8 0
3 years ago
Please Help
artcher [175]
Multiply equation B by 2.
Multiply equation A by 2
Multiply equation B by 3.
Multiply equation A by -3

Answer: D
5 0
3 years ago
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