Question

https://www.google.com/search?safe=active&q=Elvira+made+the+trip+on+Tuesday+and+David+made+the+same+trip+on+Wednesday+Elvira+traveled+at+14+mph.+David+traveled+at+21+mph,+so+his+time+was+3+hours+less+than+Elvira%27s+time.+How+far+did+they+travel?

Answer 1

Answer:Let x and (x-3) represent Elvira's and David's times respectively

D = r*t  

Distances traveled are equal in this example***

14mph*x = 21mph(x-3)

solving for x

14x = 21x - 63

 63 = 7x

x = 9hr, the time that Elvira traveled.  David traveled 6hrs   (9hr-3hr = 6hr)

CHECKING our Answer***

14mph*9hr = 126mi = 21mph*6hr = 126mi

Step-by-step explanation: