Answer:
3x^3y − 5xy^2 + 9
Step-by-step explanation:
When there is only one denominator term, the quotient can be found by dividing the numerator terms individually.
_____
There are a couple of things to keep in mind here:
- an exponent tells the number of times the factor is repeated
- equal numbers of identical factors cancel from numerator and denominator, for example x^3/x = (x·x·x)/x = x·x = x^2. (One factor of x cancels.)
Answer:
x = 18
Step-by-step explanation:
Given ![3 \sqrt[4]{(x-2)^3}-4 = 20](https://tex.z-dn.net/?f=3%20%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D-4%20%3D%2020)
now adding '4' on both sides, we get
![3 \sqrt[4]{(x-2)^3}-4+4= 20+4](https://tex.z-dn.net/?f=3%20%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D-4%2B4%3D%2020%2B4)
![3 \sqrt[4]{(x-2)^3} = 24](https://tex.z-dn.net/?f=3%20%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20%3D%2024)
i) ![3 \sqrt[4]{(x-2)^3}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D)
= <u>24</u>
cancelling '3' on both sides, we get
![\sqrt[4]{(x-2)^3} = 8](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20%3D%208)
ii) ![\sqrt[4]{(x-2)^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D)
= <u> 8</u>
<u>iii) </u>
<u></u>
<u></u>
<u></u>
iv) 
now simplify on both sides,we get
simplify we get solution is
<u>v) (x-2) </u>= 16
<u>vi) final answer is x = 16 +2 =18</u>
<u></u>
Each number is being multiplied by 3.
The answer is
(x,y)= (2,0)
ABCD is a parallelogram ⇒ BE = DE
So: 7x - 12 = 3x + 4
⇔ 7x - 3x = 4 + 12
⇔ 4x = 16
⇔ x = 16/4 = 4
⇒ BE = 7(4) - 12 = 28 - 12 = 16
⇒ DE = 3(4) + 4 = 12 + 4 = 16
⇒ BD = BE + DE = 16 + 16 = 32
Answer: BD = 32
Ok done. Thank to me :>
