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umka2103 [35]
3 years ago
15

A right cylindrical container perfectly holds 5 tennis balls placed one above the other. The radius of each ball is 3.35 centime

ters. What is the approximate volume of the unoccupied space in the container?
Mathematics
1 answer:
mash [69]3 years ago
5 0

Answer: 394 cm3


Step-by-step explanation:

volume of cylinder - volume of 5 balls=extra volume

voc=πr2h=1181.09

pi=22/7

r=3.35

h= 5 x diameter of ball=33.5 (diameter = 2r)


vo5b=5(4/3πr3)=787.4

r=3.35

ev=voc-vo5b

=393.69


ROUND TO 394

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