A right cylindrical container perfectly holds 5 tennis balls placed one above the other. The radius of each ball is 3.35 centime
ters. What is the approximate volume of the unoccupied space in the container?
1 answer:
Answer: 394 cm3
Step-by-step explanation:
volume of cylinder - volume of 5 balls=extra volume
voc=πr2h=1181.09
pi=22/7
r=3.35
h= 5 x diameter of ball=33.5 (diameter = 2r)
vo5b=5(4/3πr3)=787.4
r=3.35
ev=voc-vo5b
=393.69
ROUND TO 394
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