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umka2103 [35]
3 years ago
15

A right cylindrical container perfectly holds 5 tennis balls placed one above the other. The radius of each ball is 3.35 centime

ters. What is the approximate volume of the unoccupied space in the container?
Mathematics
1 answer:
mash [69]3 years ago
5 0

Answer: 394 cm3


Step-by-step explanation:

volume of cylinder - volume of 5 balls=extra volume

voc=πr2h=1181.09

pi=22/7

r=3.35

h= 5 x diameter of ball=33.5 (diameter = 2r)


vo5b=5(4/3πr3)=787.4

r=3.35

ev=voc-vo5b

=393.69


ROUND TO 394

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Answer:

Question 1:

The angles are presented here using Autocad desktop application

The two column proof is given as follows;

Statement                   {}                             Reason

S1. Line m is parallel to line n       {}            R1. Given

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S5. ∠2 is supplementary to ∠3 {}      R5. Linear pair angles are supplementary

S6. m∠2 + m∠3 = 180°              {}                Definition of supplementary angles

S7. m∠1 + m∠3 = 180°              {}                 Substitution Property of Equality  

S8. ∠1 is supplementary to ∠3           {}      Definition of supplementary angles

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