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sergejj [24]
3 years ago
15

What is the 24th term in the following sequence of -9,-2,5,12.

Mathematics
1 answer:
Artyom0805 [142]3 years ago
3 0

Answer:

12

Step-by-step explanation:

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Solve for x. 5 1/2 ≥ 1.6x<br> x ≥3 7/16<br> x ≤ 3 7/16<br> x ≥ 8 4/5<br> x ≤ 8 4/5
11Alexandr11 [23.1K]

Answer:

x < 3 7/16

Step-by-step explanation:

8 0
3 years ago
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Find the pressure exerted by a force of 240 N on an area of 30 cm2. Find the answer in SI unit​
NeTakaya

Answer:

<u>Pressure</u><u> </u><u>is</u><u> </u><u>8</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u> </u><u>pascals</u><u>.</u>

Step-by-step explanation:

Area:

= { \bf{ 30 \times  {10}^{ - 4}   \:  {m}^{2} }}

Pressure:

{ \bf{pressure =  \frac{force}{area} }} \\  \\  { \tt{ =  \frac{240}{30 \times  {10}^{ - 4} } }} \\  = { \tt{80000 \: pascals}}

4 0
3 years ago
To find the quotient of 4 ÷ 1 8 , count the number of in four whole circles.
SSSSS [86.1K]

Answer:

what are u asking ?? I'm confused

5 0
3 years ago
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Domain of the function of a graph with coordinates (-3,-2)
olga2289 [7]

Answer:

Domain is -3

Step-by-step explanation:

Given that coordinate of a graph is (-3, -2)

We have to find out the domain.

We know that if A and B are two sets, a mapping from A to B is the subset of cartesian product AxB.

Domain is the set of values of A which have images in B.

Use the above definition.

We have A = {-3,...} and B = {-2,....}

The mapping is from -3 to -2

Hence domain is -3

6 0
3 years ago
Iv)<br>6x+3y=6xy<br>2x + 4y= 5xy​
Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) =  (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5  - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0
3 years ago
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