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3 years ago

Which ordered pairs could be points on a line parallel to the line that contains (3, 4) and (–2, 2)? Check all that apply.

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

5 0

Answer:

bde

Step-by-step explanation:

Aleksandr-060686 [28]3 years ago

3 0

Answer:

Step-by-step explanation:

As we go from (–2, 2) to (3, 4), x increases by 5 and y increases by 4. Thus, the slope of the line through (–2, 2) and (3, 4) is

m = rise / run = 4/5.

Use the slope-intercept form of the equation of a straight line:

y = mx + b becomes 4 = (4/5)(3) + b. Multiplying all three terms by 5, we eliminate the fraction: 20 = 12 + b. Thus, b = 8, and the equation of the line through (–2, 2) and (3, 4) is y = (4/5)x + 8.

A line parallel to this one would have the form y = (4/5)x + b; note that the slopes of these two lines are the same, but the y-intercept, b, would be different if the two lines do not coincide.

Unfortunately, you have not shared the ordered pairs given in this problem statement.

You could arbitrarily let b = 0. Then the parallel line has equation

y = (4/5)x; if x = 3, then y = (4/5)(3) = 12/5, and so (3, 12/5) lies on the parallel line.

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An automobile manufacturer has given its car a 52.6 miles/gallon (MPG) rating. An independent testing firm has been contracted t

Arte-miy333 [17]

Answer:

Null hypothesis: $\mu = 52.6$

Alternative hypothesis: $\mu \neq 52.6$

$z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976$

$p_v =2*P(z>1.976)=0.0482$

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

Step-by-step explanation:

Information provided

$\bar X=52.8$ represent the sample mean for the MPG of the cars

$\sigma=1.6$ represent the population standard deviation

$n=250$ sample size of cars

$\mu_o =52.6$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test

Hypothesis

We need to conduct a hypothesis in order to check if the true mean of MPG is different from 52.6 MPG, the system of hypothesis would be:

Null hypothesis: $\mu = 52.6$

Alternative hypothesis: $\mu \neq 52.6$

Since we know the population deviation the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Calculate the statistic

Replacing we have this:

$z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976$

Decision

Since is a two tailed test the p value would be:

$p_v =2*P(z>1.976)=0.0482$

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

3 0

3 years ago

A chemical spill is leaking into a river flowing 2 3/4 miles per hour. How long will it take the chemicals to reach a town locat

ExtremeBDS [4]

Answer:

$6\frac{3}{11}=6.27$ hours.

Step-by-step explanation:

We have been given that a chemical spill is leaking into a river flowing 2 3/4 miles per hour.

To find the time taken by chemical to reach the town we will divide distance of town from the spill by distance covered by chemical spill in one hour.

$\text{Time taken by chemical to reach the town}=17\frac{1}{4} \div 2\frac{3}{4}$