Please help<br><br>thank you

Solve this equation for x 0.95 = log x

Lelechka [254]

Answer:

8.91

Step-by-step explanation:

Given: 0.95 = log x,

we can conclude that:

0.95 log x

10 = 10

0.95

which in turn is equivalent to x = 10 whose value is 8.91

5 0

3 years ago

What is j(4) if j(m)=2^m-1

Lady_Fox [76]

2^4-1 so 2•2•2•2=16 and 16-1 is 15

5 0

3 years ago

Construct the confidence interval for the population mean mu. c = 0.90, x = 16.9, s = 9.0, and n = 45. A 90% confidence inte

Georgia [21]

Answer:

The 90% confidence interval for population mean is $14.7 < \mu < 19.1$

Step-by-step explanation:

From the question we are told that

The sample mean is $\= x = 16.9$

The confidence level is $C = 0.90$

The sample size is $n = 45$

The standard deviation

Now given that the confidence level is 0.90 the level of significance is mathematically evaluated as

$\alpha = 1-0.90$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the standardized normal distribution table. The values is $Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining critical values for $\frac{\alpha }{2}$ instead of that of $\alpha$ is because $\alpha$ represents the area under the normal curve where the confidence level 1 - $\alpha$ (90%) did not cover which include both the left and right tail while $\frac{\alpha }{2}$ is just considering the area of one tail which is what we required calculate the margin of error