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The class scores of a history test have a normal distribution with a mean Mu = 79 and a standard deviation Sigma = 7. If Opal’s

storchak [24]

The value of z score for the history class test of Opal’s test score is negative one (-1).

<h3>What is normally distributed data?</h3>

Normally distributed data is the distribution of probability which is symmetric about the mean.

The mean of the data is the average value of the given data. The standard deviation of the data is the half of the difference of the highest value and mean of the data set.

The z score for the normal distributed data can be given as,

$Z=\dfrac{X-\mu}{\sigma}$

The mean value of the scores of history class is,

$\mu=79$

The standard deviation value of the scores of history class is,

$\sigma=7$

Here, the test score of the Opal’s is 72. Thus the z score for her test score can be given as,

$z=\dfrac{72-79}{7}\\z=-1$

Hence, the value of z score for the history class test of Opal’s test score is negative one (-1).

Learn more about the normally distributed data here;

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6 0

2 years ago

Please anybody help me ASAP

Yuki888 [10]

Answer:

4 cents

Step-by-step explanation:divide 2 dy 5 to get the unit price hope this helps god bless

8 0

3 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about quadratic equations:

brainly.com/question/27638369

6 0

2 years ago

Read 2 more answers

Find the slope of the line that contains the following points: (2, 12) and (4, -24)

TiliK225 [7]

Answer:

slope is change in rise(y) over change in run (x), change in y here is 36 and change in x is 2, slope is 36/2=18

8 0

2 years ago

Suppose that F(x) = x^2 and G(x) = 2x^2-5. Which statement best compares the graph G(x) with the graph of F(x)?

notsponge [240]

I believe the correct answer from the choices listed above is option D. The graph G(x) as compared to the graph of F(x) would be that the graph of G(x) is the graph of F(x) stretched vertically and shifted 5 units down. 2 is a stretch factor and -5 is the shift downwards of the graph. Hope this answers the question.

8 0

3 years ago

Read 2 more answers

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