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Aleonysh [2.5K]
3 years ago
5

How do I solve these trigonometric equations!!?

Mathematics
1 answer:
iogann1982 [59]3 years ago
4 0

Answer:

Solution are

i) x = 0, \pi, \frac{3\pi}{2} , 2\pi

Step-by-step explanation:

1) (sinx)(cosx) =0

sin2x/2 =0

2x =0, 2pi, 3pi, 4pi

Hence x = 0, \pi, \frac{3\pi}{2} , 2\pi

---------------------------

2) cos2x + 2 cos x + 1 = 0\\2cos^2 x +2cosx +1 =0\\(cosx+1)^2 =0\\cosx =-1\\x=\pi

----------------------

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