Answer:
The weight of pure gold in 258 g rams of 18- karat gold is 193.5 grams.
Step-by-step explanation:
The pure percentage in the gold = 75%
The weight of the gold purchased = 258 g
Now, here the pure gold percentage is 75% of 258 g
75% of 258 grams = 
or,
⇒75% of 258 grams = 193.5 grams
Hence, the weight of pure gold in 258 g rams of 18- karat gold is 193.5 grams.
When writing an informative essay about an event in history, you should:
- Pick an engaging topic with several sources of information.
- Clearly state your thesis in your introduction.
- Use every paragraph to expand on a separate point.
- Avoid using long sentences.
- Reference sources accurately.
<h3>How can you write an informative essay on historical events?</h3>
To avoid finding it difficult to find information on your topics, pick a topic that has been well researched and has several sources of information on it. European history is well researched.
In the introduction, talk about why you think this topic is significant and include a thesis statement that would be the main logic you are producing details about.
Then divide this thesis into several points and talk about each point in a different paragraph. Use sentences that are not too long so that people don't lose interest.
Use primary and secondary information sources but make sure you reference these sources in the required format.
Find out more on informative essays at brainly.com/question/329730.
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Answer: So first you need to multiply the 2 numbers together. When you multiply them together you get 32.528. Nobody pays you .528 censt to you just cut off that number. I hope this answered your question.
Answer:
16.5 m
Step-by-step explanation:
Hi there!
Set up a proportion (letting h = the height of the tree):

Multiply both sides by 22 to isolate <em>h</em>:
6/8 * 22 = h
h = 16.5
Therefore, the height of the tree is 16.5 m.
I hope this helps!
Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1