Hey there, Lets solve this problem together.
Our first step will be to g<span>ather like terms
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Simplify 5×−2k×k to −5×2k×k
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Simplify <span><span>5×2k×k</span></span><span> to </span><span><span>10<span>k^2
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Answer:
y = - 9x + 15
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - 9x - 2 ← is in slope- intercept form
with slope m = - 9
Parallel lines have equal slopes, thus
y = - 9x + c ← is the partial equation
To find c substitute (2, - 3) into the partial equation
- 3 = - 18 + c ⇒ c = - 3 + 18 = 15
y = - 9x + 15 ← equation of parallel line
Answer:
where is the rest...........is that all?
Answer:
A) (-5, -34)
Step-by-step explanation:
f(x) = x^2 + 10x - 9
We complete the square to get the equation in vertex form
Take the coefficient of the x term and divide by 2 then square it. We add it and then subtract it not to change the value of the equation
f(x) = x^2 + 10x +(10/2)^2 - (10/2)^2 - 9
f(x) = x^2 +10x +25 -25 -9
f(x) = (x^2 +10x +25) -34
The term in parentheses simplified to (x+10/2) ^2
= (x+5)^2 -34
= (x - -5)^2 -34
This is in the form (x-h)^2 +k
The vertex is (h,k) h=-5 and k=-34
(-5,-34)
