Answer:
The perimeter of ∆ABC is ![P=14.35\ units](https://tex.z-dn.net/?f=P%3D14.35%5C%20units)
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
When a circle has an inscribed angle that "cuts out" a semi-circle, like the one in the attached figure, then the inscribed angle is a right angle. so
m∠C=90°
The perimeter of triangle ABC is equal to
![P=AB+BC+AC](https://tex.z-dn.net/?f=P%3DAB%2BBC%2BAC)
----> is equal to the diameter of the circle
<em>Find the length side AC</em>
![cos(35\°)=\frac{AC}{AB}](https://tex.z-dn.net/?f=cos%2835%5C%C2%B0%29%3D%5Cfrac%7BAC%7D%7BAB%7D)
![AC=cos(35\°)(AB)](https://tex.z-dn.net/?f=AC%3Dcos%2835%5C%C2%B0%29%28AB%29)
substitute
![AC=cos(35\°)(6)=4.91\ units](https://tex.z-dn.net/?f=AC%3Dcos%2835%5C%C2%B0%29%286%29%3D4.91%5C%20units)
<em>Find the length side BC</em>
![sin(35\°)=\frac{BC}{AB}](https://tex.z-dn.net/?f=sin%2835%5C%C2%B0%29%3D%5Cfrac%7BBC%7D%7BAB%7D)
![BC=sin(35\°)(AB)](https://tex.z-dn.net/?f=BC%3Dsin%2835%5C%C2%B0%29%28AB%29)
substitute
![BC=sin(35\°)(6)=3.44\ units](https://tex.z-dn.net/?f=BC%3Dsin%2835%5C%C2%B0%29%286%29%3D3.44%5C%20units)
<em>Find out the perimeter</em>
![P=AB+BC+AC](https://tex.z-dn.net/?f=P%3DAB%2BBC%2BAC)
substitute
![P=6+3.44+4.91=14.35\ units](https://tex.z-dn.net/?f=P%3D6%2B3.44%2B4.91%3D14.35%5C%20units)
Answer:
Yes! Good job!
If you can pick multiple its also C. and B.
Answer:
The surface area formula for a cone, given its diameter (or radius) and height, is π x (diameter / 2) 2 + π x (diameter / 2) x √ (diameter / 2) 2 + (height 2), where (diameter / 2) is the radius of the base (d = 2 x r), so another way to write it is π x radius 2 + π x radius x √ (radius 2 + (height 2)