Answer:
it will dilute to its natrual state. so c
Explanation:
Hi!
The correct options would be:
1. Cathode - <em>reduction</em>
The cathode is the negatively charged electrode, and so has an excess of electrons. Cations (positively charged ions) are attracted to the cathode, and gain electrons to acquire a neutral charge. The process in which a gain of electron occurs is called reduction.
2. Anode - <em>oxidation</em>
The opposite occurs at the anode which is positively charged and attracts negatively charged ions, anions. These anions lose their electrons at the anode to acquire a neutral charge, and the process involving loss of electrons is known as oxidation.
3. Salt Bridge - <em>ion transport </em>
Salt bridge is a physical connection between the the anodic and cathodic half cells in an electrochemical cell and is a pathway that facilitates the flow of ions back and forth these half cells. Salt bridge is involved in maintaining a neutral condition in the electrochemical cells, and its absence would result in the accumulation of positive charge in the anodic cell, and negative charge in the cathodic cell.
4. Wire - <em>electron transport </em>
Wires have a universal role of being a pathway for the transport of electrons in circuit. This role is also the same in the wires involved in an electrochemical cells where they are used to transport electrons from the anodic half cell, and this electron transport results in the generation of electricity in the internal circuit of the electrochemical cell.
Hope this helps!
Answer:
The answer to your question is: C₃H₃O This is my answer.
Explanation:
Data
Sample = 1.3109 g
CxHyOz
CO₂ = 3.2007 g
H₂O = 1.3102 g
Empirical formula = ?
MW CO2 = 44 g
MW H2O = 18 g
For Carbon
44 g -------------------- 12 g
3.2007 g ------------ x
x = (3.2007 x 12) / 44
x = 0.8729 g of Carbon
12 g of C -------------- 1 mol
0.8729 g -------------- x
x = (0.8729 x 1) / 12
x = 0.0727 mol of Carbon
For Hydrogen
18 g ---------------------- 1 g
1.3102 g ------------------- x
x = (1.3102 x 1) / 18
x = 0.0727 g of Hydrogen
1 g ------------------------ 1 mol
0.0727g ---------------- x
x = (0.0727 x 1)/1
x = 0.0727 mol of Hydrogen
For oxygen
g of Oxygen = g of sample - g of Carbon - g of hydrogen
g of Oxygen = 1.3109 - 0.8709 - 0.0727
g of Oxygen = 0.3673
16 g of Oxygen ------------- 1 mol of O
0.3673 g --------------------- x
x = (0.3673 x 1)/ 16
x = 0.0230 mol of Oxygen
Divide by the lowest number of moles
Carbon 0.0727 / 0.023 = 3.1 ≈ 3
Hydrogen 0.0727 / 0.023 = 3.1 ≈ 3
Oxygen 0.0230 / 0.023 = 1
C₃H₃O
It either forms a base or an acid...I think that's the answer you're looking for
Answer:
The potential energy decreases whereas the kinetic energy increases.
