Answer:
The upper and lower limits for the room-temperature thermal conductivity of a magnesium oxide material having a volume fraction of 0.10 of pores that are filled with still air are
Ku = 38.252 W/mK
K lower = 0.199 W/mK
Explanation:
As we know
Ku = Vp * Kair + Vmagnesium * K metal
Ku = 0.10 *0.02 + (1-0.25) * 51
Ku = 38.252 W/mK
The lower limit
K lower = Kmetal* Kair/( Vp * Kmetal + Vmetal * K air)
K lower = (0.02*51)/(0.10*51 + 0.90 * 0.02)
K lower = 0.199 W/mK
No, the formation of dew is condensation, which is a physical change.
Answer:
B- fission breaks apart nuclei; fusion puts them back together
<span>Feb 19, 2014 - The units of k tell you that this is a second order reaction. So, to solve this, you need to use the integrated rate law for a 2nd order reaction: 1/[A] = kt + 1/[A]o 1/[A] = 0.540/Ms (835 s) + 1/0.00640 1/[A] = 607 [A] = 1.65X10^-3 M.</span><span>
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<u>Answer:</u> The mass of ice is 
<u>Explanation:</u>
We are given:
Area of Antarctica = 
(Conversion factor: 
)
Height of Antarctica with ice = 7500 ft.
Height of Antarctica without ice = 1500 ft.
Height of ice = 7500 - 1500 = 6000 ft = 
(Conversion factor: 1 ft = 30.48 cm)
To calculate mass of ice, we use the equation:
We are given:
Density of ice = 
Volume of ice = Area × Height of ice = 
Putting values in above equation, we get:
Hence, the mass of ice is
