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g100num [7]
3 years ago
8

Join me in among us if u want :) sever code-XXILYQ

Chemistry
2 answers:
myrzilka [38]3 years ago
8 0

Answer:

cool. mind giving brainliest?

maria [59]3 years ago
4 0

Answer:

im so down but where do you go?

Explanation:

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The element thallium is 70% thallium-205 and 30% thallium-203. Calculate its relative atomic mass to 1 decimal place.
xxMikexx [17]

Answer:

answer-

The relative atomic mass = 204.4

explanation:

Thallium -203 = 30%

Thallium -205 = 70%

Therefore ,

relative mass of thallium = (30×203 + 70×205)/100

relative mass of thallium = (20440)/100

relative mass of thallium = 204.40 amu

Thus,

relative atomic mass of thalium =204.4 ( to 1 decimal place)

6 0
3 years ago
What is a molarity a measurement
USPshnik [31]

Answer:

Molarity indicates the number of moles of solute per liter of solution and is one of the most common units used to measure the concentration of a solution.

Explanation:

8 0
3 years ago
Keep your work area neal and
Sindrei [870]
Clean? I’m pretty sure not sure what it means but.
8 0
2 years ago
An electron can be added to halogen atom to force a halide ion with
Lilit [14]

An electron can be added to halogen atom to force a halide ion with 8 valence electrons

<h3>What is an atom?</h3>

An atom can be defined as the smallest part of an element which can take part in a chemical reaction.

However whenever, an electron is added to halogen atom to force a halide ion with 8 different valence electrons

So therefore; an electron can be added to halogen atom to force a halide ion with 8 valence electrons

Learn more about halogens:

brainly.com/question/18276987

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4 0
2 years ago
. In a titration, a 25.0 mL sample of 0.150 M HCl is neutralized with 44.45 mL of Ba(OH)2. a. Write the balanced molecular equat
choli [55]

Answer:

Equation of reaction:

a) 2HCl + Ba(OH)2 ==> CaCl2 + 2H2O

b) Molarity of base = 0.042 M.

Explanation:

Using titration equation

CAVA/CBVB = NA/NB

Where NA is the number of mole of acid = 2

NB is the number of mole of base = 1

CA is the molarity of acid =0.15M

CB is the molarity of base = to be calculated

VA is the volume of acid = 25 ml

VB is the volume of base = 44.45mL

Substituting

0.15×25/CB×44.45 = 2/1

Therefore CB =0.15×25×1/44.45×2

CB = 0.042 M.

5 0
2 years ago
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