3 years ago

Join me in among us if u want :) sever code-XXILYQ

Chemistry

2 answers:

myrzilka [38]3 years ago

8 0

Answer:

cool. mind giving brainliest?

maria [59]3 years ago

4 0

Answer:

im so down but where do you go?

Explanation:

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A 52-gram sample of water that has an initial temperature of 10.0 °C absorbs 4,130 joules. If the specific heat of water is 4.18

FinnZ [79.3K]

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The final temperature of the water is 28.98 degree Celsius.

Explanation:

It is given that,

Mass of sample of water, m = 52 grams

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The specific heat of water is $4.184\ J/(g^{\circ} C)$

We need to find the final temperature of the water. The heat absorbed is given by the formula as follows :

$Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\T_f=\dfrac{Q}{mc}+T_i\\\\T_f=\dfrac{4130}{52\times 4.184 }+10\\\\T_f=28.98^{\circ} C$

So, the final temperature of the water is 28.98 degree Celsius.

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