3 years ago

Join me in among us if u want :) sever code-XXILYQ

Chemistry

2 answers:

myrzilka [38]3 years ago

8 0

Answer:

cool. mind giving brainliest?

maria [59]3 years ago

4 0

Answer:

im so down but where do you go?

Explanation:

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Enough of a monoprotic weak acid is dissolved in water to produce a 0.0144 0.0144 M solution. The pH of the resulting solution i

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The value of dissociation constant of the monoprotic acid is $1.099\times 10^{-3}$ .

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The pH of the solution = 2.46

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$HA\rightleftharpoons H^++A^-$

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The expression if an dissociation constant is given by :

$K_a=\frac{[A^-][H^+]}{[HA]}$

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$K_a=\frac{0.003467 \times 0.003467 }{(0.0144-0.003467 )}$

$K_a=1.099\times 10^{-3}$

The value of dissociation constant of the monoprotic acid is $1.099\times 10^{-3}$ .

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