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denis23 [38]
3 years ago
7

An experiment involves selecting a random sample of 256 middle managers for study. One item of interest is their annual income.

The sample mean is computed to be $35,420. If the population standard deviation is $2,050, what is the standard error of the mean
Mathematics
1 answer:
yulyashka [42]3 years ago
4 0

Answer:

SE=$128.13

Step-by-step explanation:

-Given the sample mean is $34,250 and standard deviation is $2,050 with n=256:

-Standard error is calculated using the formula:

SE=\frac{s}{\sqrt{n}}

Where s is the sample standard deviation.

#We substitute our values to solve for SE:

SE=\frac{s}{\sqrt{n}}\\\\=\frac{2050}{\sqrt{256}}\\\\=128.125\approx128.13

Hence, the standard error is $128.13

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The areas of the parallelograms can be compared as: A. The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.

<h3>What is a parallelogram?</h3>

A parallelogram refers to a geometrical shape and it can be defined as a type of quadrilateral and two-dimensional geometrical figure that has two (2) equal and parallel opposite sides.

<h3>How to calculate the area of a triangle?</h3>

Mathematically, the area of a triangle can be calculated by using this formula:

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<h3>How to calculate the area of a rectangle?</h3>

Mathematically, the area of a rectangle can be calculated by using this formula;

A = LW

Where:

  • A represents the area of a rectangle.
  • l represents the length of a rectangle.
  • w represents the width of a rectangle.

Next, we would determine the area of the two parallelograms as follows:

Area of parallelogram 1 = Area of red-rectangular figure - Area of triangle A - Area of triangle B - Area of triangle C - Area of triangle D.

Substituting the given parameters into the formula, we have;

Area of parallelogram 1 = (6 × 6) - (½ × 4 × 2) - (½ × 2 × 4)- (½ × 4 × 2) - (½ × 2 × 4)

Area of parallelogram 1 = 36 - 4 - 4 - 4 - 4

Area of parallelogram 1 = 36 - 16

Area of parallelogram 1 = 20 units².

For parallelogram 2, we have:

Area of parallelogram 2 = Area of blue-rectangular figure - Area of triangle P - Area of triangle Q - Area of triangle R - Area of triangle S.

Substituting the given parameters into the formula, we have;

Area of parallelogram 2 = (8 × 4) - (½ × 2 × 2) - (½ × 6 × 2)- (½ × 2 × 2) - (½ × 2 × 6)

Area of parallelogram 2 = 32 - 2 - 6 - 2 - 6

Area of parallelogram 2 = 32 - 16

Area of parallelogram 2 = 16 units².

Difference = Area of parallelogram 1 - Area of parallelogram 2

Difference = 20 - 16

Difference = 4 units².

In conclusion, we can infer and logically deduce that the area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.

Read more on parallelogram here: brainly.com/question/4459854

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