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denis23 [38]
2 years ago
7

An experiment involves selecting a random sample of 256 middle managers for study. One item of interest is their annual income.

The sample mean is computed to be $35,420. If the population standard deviation is $2,050, what is the standard error of the mean
Mathematics
1 answer:
yulyashka [42]2 years ago
4 0

Answer:

SE=$128.13

Step-by-step explanation:

-Given the sample mean is $34,250 and standard deviation is $2,050 with n=256:

-Standard error is calculated using the formula:

SE=\frac{s}{\sqrt{n}}

Where s is the sample standard deviation.

#We substitute our values to solve for SE:

SE=\frac{s}{\sqrt{n}}\\\\=\frac{2050}{\sqrt{256}}\\\\=128.125\approx128.13

Hence, the standard error is $128.13

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Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

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Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

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Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

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Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

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Plug into x-y=2---> x-3=2---> x=5

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Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

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First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

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Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

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Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

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