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Ne4ueva [31]
3 years ago
12

In a survey of students at a local high school, 30% of the students said they liked tater tots and 15% of the students said they

like French fries. If every one of the students who said they like French fries also said they like tater tots, what proportion of the students responding to the survey said they liked at least one of the two side dishes?
Mathematics
2 answers:
Tom [10]3 years ago
7 0

Answer:  0.30

Step-by-step explanation:

Let T denotes tater tots and F denotes French fries .

As per given ,

The proportion of students said they liked tater tots : <em>P(T)=</em> 0.30

The proportion of of students said they like French fries : <em>P(F)</em>= 0.15

Since , every one of the students who said they like French fries also said they like tater tots.

i.e. <em>P(T∩F)</em> = 0.15

Now , using addition formula , we have

<em>P(T∪F)= P(T)+P(F)-P(T∩F)</em>

= 0.30+0.15-0.15=0.30

Hence, the proportion of the students responding to the survey said they liked at least one of the two side dishes is 0.30.

Artemon [7]3 years ago
4 0
Based on the given problem above, the proportion of the students responding to the survey that said that they liked at least one of the two side dishes is 3/10. Because<span> 30% said they like tater tots and all the ones who said they liked fries are the same people then you're only looking at the 30% wherein 30/100 is 3/10 which makes 3/10 the right answer.</span>
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Saul decides to use the IQR to measure the spread of the data. Saul calculates the IQR of the data set to be 27
german

Answer:

n = 78

Step-by-step explanation:

IQR is the interquartile range of the data set.

So Saul had already arranged the data in order, that is the first step when calculating the interquartile range.

25, 30, 50, 50, 50, 50, 56, n., 250

Next, is to find the median so we could easily separate the data into quartiles.

The median of the data 25, 30, 50, 50, 50, 50, 56, n., 250 = 50

Then, arrange the data into the first quartile and the third quartile

first quartile = 25, 30, 50, 50

third quartile = 50, 56, n., 250

first quartile median = 30 + 50 = 80/2 = 40

third quartile = 56 + n /2

The interquartile range formula is the first quartile subtracted from the third quartile:

IQR = Q3 – Q1.

Since 27 is the interquartile range, n=

27 = (56 + n /2) - 40

Use 2 to multiply through to eliminate the denominator

54 = (56 + n) - 80

n = 78

5 0
3 years ago
During a fundraiser, John raised $50, Susan raised $72, and Kara raised $65. Who has the greatest magnitude of money raised?
TiliK225 [7]

Answer:

Susan has the most money which is $72

Step-by-step explanation:

because john has $50 which is lower than $72 and kara has $65 which is lower than $72 so therefore susan has more money

5 0
2 years ago
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If x=2, y=3 and z=1 then find the value of <br> 1/2 x + 3/4 y
Nuetrik [128]

Answer:

1 1/4

Step-by-step explanation:

x=2, y=3, and z=1

1/2(2)+3/4(3)=1+3/12=1 1/4

7 0
3 years ago
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A right angled triangle has sides of length 9cm, 12cm and 15cm. Calculate its area in square centimetres.
Dmitriy789 [7]

The area of a right angled triangle with sides of length 9cm, 12cm and 15cm in square centimeters is 54 sq cm.

The formula to calculate the area of a right triangle is given by:

Area of Right Triangle, A = (½) × b × h square units

Where, “b” is the base (adjacent side) and “h” is the height (perpendicular side). Hence, the area of the right triangle is the product of base and height and then divide the product by 2.

We know that the hypotenuse is the longest side. So, the area of a right angled triangle will be half of the product of the remaining two sides.

Given sides of the triangle:

a=9cm

b=12cm

c=15cm

From this we know that the hypotenuse is c. Are of the triangle will be obtained by the other two sides.

∴Area = \frac{1}{2} x 9 x 12

= 54cm^{2}

5 0
1 year ago
You go to an arcade and purchase a card with game credits. After playing 5 games you have 33 credits left. You play 4 more games
Amanda [17]

Answer:

y=-3x+48

Step-by-step explanation:

We will use slope-intercept form of equation to write our equation. The equation of a line in slope-intercept form is: y=mx+b, where m= Slope of the line, b= y-intercept.

To write the equation that represents the number of credits y on the cards after x games, we will find slope of our line.

We have been given that after playing 5 games we have 33 credits left. We play 4 more games and we have 21 credits left. So our points will be (5,33) and (9,21).

Let us substitute coordinates of our both given points in slope formula: m=\frac{y_2-y_1}{x_2-x_1},

m=\frac{21-33}{9-5}

m=\frac{-12}{4}=-3

Now let us substitute m=-3 and coordinates of point (5,33) in slope intercept form of equation to find y-intercept.

33=-3\cdot 5+b    

33=-15+b    

33+15=b    

48=b    

Upon substituting m=-3 and b=48 in slope-intercept form of an equation we will get,

y=-3x+48

Therefore, our desired equation will be y=-3x+48.

6 0
3 years ago
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