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BigorU [14]
3 years ago
6

What is the relationship between area in the scale drawing and area on the on the actual tennis court if the scale is 1in.: 5ft.

and the length of the scale is 15.6 and the width is 7.2 in.
What is the ratio of areaof the actual court to the area of the drawing (as a unit rate)? Is it the same as the ratio of length of the actual court to the length of the drawing?
Mathematics
1 answer:
sveticcg [70]3 years ago
7 0

Given:

Length of the scale = 15.6 in.

Width of the scale = 7.2 in.

Scale of drawing = 1 in. : 5ft.

To find:

The ratio of area of the actual court to the area of the drawing (as a unit rate).

And to check whether it is the same as the ratio of length of the actual court to the length of the drawing.

Step-by-step explanation:

We have,

1 in. = 5ft.

Now, using this scale we get

15.6 in. = (15.6 × 5) ft =78 ft.

7.2 in. = (7.2 × 5) ft = 36 ft.

So, the actual length and width of tennis court are 78 ft and 36 ft respectively.

Area of actual tennis court is

Area=length\times width

Area=78\times 36

Area=2808\text{ ft}^2

The area of drawing is

Area=15.6\times 7.2

Area=112.32\text{ in.}^2

Now, ratio of area of the actual court to the area of the drawing (as a unit rate) is

\dfrac{2808}{112.32}=\dfrac{25}{1}=25:1

Ratio of area is 25:1 and ratio of length is 5:1 both area not same.

Therefore, the ratio of area of the actual court to the area of the drawing (as a unit rate) is 25:1.

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