Answer:
240
Step-by-step explanation:
If you draw a straight line, 12 would meet at 240. Hope this is helpful! You were close but I think you mixed up 240 and 300.
The common point between y = 2x + 5 and y = (1/2)x + 6 will have the same values for x and y.
Therefore, set the two y expressions equal to obtain
2x + 5 = (1/2)x + 6
Subtract (1/2)x from each side.
(3/2)x + 5 = 6
Subtract 5 from each side.
(3/2)x = 1
Multiply each side by 2/3.
x = 2/3.
From the first equation, obtain
y = 2*(2/3) + 5 = 19/3.
The common point is (2/3, 19/3). It is not equal to (3, 1/2).
Answer: False
Uhm is this a question orrrrrr
Answer:
C. 35sqcm
Step-by-step explanation:
area of rectangle = length × breadth
5×7=35
If you use this equation then you say that the ground is h=0 and solve as a quadratic.
The quadratic formula is (-b±<span>√(b^2-4ac))/2a when an equation is in the form ax^2 + bx + c
So the equation you have been given would be -16t^2-15t-151 = 0
This equation has no real roots which leads me to believe it is incorrect.
This is probably where your difficulty is coming from, it's a mistake.
The equation is formed from S=ut+(1/2)at^2+(So) where (So) is the initial height and S is the height that you want to find.
In this case you want S = 0.
If the initial height is +151 and the initial velocity and acceleration are downwards (negative) and the initial velocity (u) is -15 and the initial acceleration is -32 then you get the equation S=-15t-16t^2+151
Solving this using the quadratic formula gives you t = 2.64 or t = -3.58
Obviously -3.58s can't be the answer so you're left with 2.64 seconds.
Hope this makes sense.
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