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yarga [219]
4 years ago
14

I need help!!!! Please if you get it right i will mark you brainliest!

Mathematics
2 answers:
USPshnik [31]4 years ago
7 0
If both are negative then it is located on the 3rd quadrant


hope this helps
otez555 [7]4 years ago
4 0
An example of a point that has x < 0 and y < 0 is (-1,-1).
(-1,-1) would lie in Quadrant III (3).

So, if x < 0 and y < 0, the point (x,y) would be located in Quadrant III.

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75x1/3=25 so she has $50 left and then 1/5 of 50 is $10 so she has $40 left
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4 years ago
Explain, then show, how to prove that g(x) and g^(-1) (x) are inverse functions.
anastassius [24]

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Where is the question

Step-by-step explanation:

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3 years ago
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If you get it right, you get a brainliness!
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b

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3 years ago
Hotah and his 3 friends are each running 1/4 of a 2-mile relay race. How far is each person running?
vivado [14]

Answer:

1/2 of a mile

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5 0
4 years ago
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help please!! find the area of each triangle. round intermediate values to the nearest tenth. use the rounded values to calculat
White raven [17]

Area of a triangle = (1/2)*base*height

For both of the triangles, you have the base (8.8 for the triangle on the left, 7.6 for the triangle on the right) and the side lengths, but not the height. But since both are isosceles triangles, you can find the height using the pythagorean theorem.

5.

First divide the triangle vertically into two triangles (see attached picture). Now you have two right triangles, you can apply the pythagorean theorem on either one of them to find the height. The pythagorean theorem says that for a right triangle, a^2+b^2=c^2, where c is the hypotenuse and a and b are the sides of the triangle.

Substituting the given values and rounding to nearest tenth:

a^2+b^2=c^2\\4.4^2+h^2=10^2\\h=9.0

Now that you have the height, you can find the area of the entire triangle.

A = (1/2)*base*height

A = (1/2)*8.8*9.0 = 39.6

6.

Same procedure.

a^2+b^2=c^2\\3.8^2+h^2=10^2\\h=9.2

A = (1/2)*base*height

A = (1/2)*7.6*9.2 = 35.0

7 0
3 years ago
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