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3 years ago

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Mathematics

1 answer:

Ksju [112]3 years ago

8 0

Given : The Number of Correct Answers = 30

Given : Total Number of Questions = 40

⇒ The Number of Wrong Answers = (40 - 30) = 10

The Ratio of the Number of Correct Answers to Number of Wrong Answers is :

$\mathsf{\implies \frac{30}{10}}$

$\mathsf{\implies 3 : 1}$ (1st Blank)

The Ratio of the Number of Correct Answers to Total Number of Questions is :

$\mathsf{\implies \frac{30}{40}}$

$\mathsf{\implies 3 : 4}$

If there is 100 Questions on the test and the Ratio stayed the same, The Number of Questions he would have answered correctly is :

$\mathsf{\implies \frac{3}{4} \times Total\;Number\;of\;Questions}$

$\mathsf{\implies \frac{3}{4} \times 100}$

$\mathsf{\implies (3 \times 25)}$

$\mathsf{\implies 75}$ (2nd Blank)

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Match the features of the graph of the rational function.

Sunny_sXe [5.5K]

After applying algebraic analysis we find the right choices for each case, all of which cannot be presented herein due to length restrictions. Please read explanation below.

<h3>How to analyze rational functions</h3>

In this problem we have a rational function, whose features can be inferred by algebraic handling:

Holes - x-values that do not belong to the domain of the rational function:

x³ + 8 · x² - 9 · x = 0

x · (x² + 8 · x - 9) = 0

x · (x + 9) · (x - 1) = 0

x = 0 ∨ x = - 9 ∨ x = 1

But one root is an evitable discontinuity as:

y = (9 · x² + 81 · x)/(x³ + 8 · x² - 9 · x)

y = (9 · x + 81)/(x² + 8 · x - 9)

Thus, there are only two holes. (x = - 9 ∨ x = 1) Besides, there is no hole where the y-intercept should be.

Vertical asymptotes - There is a vertical asymptote where a hole exists. Hence, the function has two vertical asymptotes.

Horizontal asymptotes - Horizontal asymptote exists and represents the end behavior of the function if and only if the grade of the numerator is not greater than the grade of the denominator. If possible, this assymptote is found by this limit:

$y = \lim_{x \to \pm \infty} \frac {9\cdot x + 81}{x^{2}+8\cdot x - 9}$

y = 0

The function has a horizontal asymptote.

x-Intercept - There is an x-intercept for all x-value such that numerator is equal to zero:

9 · x + 81 = 0

x = - 9

There is a x-intercept.

Lastly, we have the following conclusions:

How many holes? 2
One horizontal asymptote along the line where y always equals what number: 0
This function has x-intercepts? True
One vertical asymptote along the line where x always equals what number: 1
There is a hole where the y-intercept should be? False

To learn more on rational functions: brainly.com/question/27914791

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2 years ago

14 80 tiles of side 30cm were used to cover a counter top. Calculate the area of the counter top in square metres.

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Answer:

Step-by-step explanation:

1,480 is a lot of tiles. Did you mean 80 tiles?

30 cm = 0.3 m

Area of one tile = 0.3² m² = 0.09 m²

Multiply the number of tiles by 0.09 m².

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3 years ago

a school wants to make a new playground by cleaning up and abandoned lot that is shaped like a rectangle. they give the job of p

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3/8 is left is the correct answer if multiple choice

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3 years ago

Pleaseeeee anyone want to help me on this??? WILL MARK BRIANLIEST

wel

Answer:

The Length of JK is 10

Step-by-step explanation:

Because <J is congruent to <L we know that the triangle in question must be isosceles as in an isosceles triangle two angles opposite of each other are equal. (This is also true for equilateral triangles, however, in an equilateral triangle all sides must be congruent, so we can rule equilateral out as LJ is not congruent to KL.) This means that the triangle must be isosceles.

In an isosceles triangle the side opposite each other are congruent, and the angles opposite each other are congruent when split down the line of symmetry.

Therefor, the length of JK must be congruent to the length of KL. In other words if JK = 10, then KL must equal 10 as well.

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3 years ago

Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar

Mamont248 [21]

Answer:

The 95% confidence interval is

$0.7811 < p < 0.9529$

Generally the interval above can interpreted as

There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval

Generally 99% is outside the interval obtained in a above then the claim of Wal-mart is not believable

$n = 125 \ stores$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The number of stores that had more than 2 items price incorrectly is k = 52

Generally the sample proportion is mathematically represented as

$\^ p = \frac{ k }{ n }$

=> $\^ p = \frac{ 52 }{ 60 }$

=> $\^ p = 0.867$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.96 * \sqrt{\frac{ 0.867 (1- 0.867)}{60} }$

=> $E = 0.0859$

Generally 95% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.867 - 0.0859 < p < 0.867 + 0.0859$

=> $0.7811 < p < 0.9529$

Generally the interval above can interpreted as

There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval

Considering question b

Generally 99% is outside the interval obtained in a above then the claim of Wal-mart is not believable

Considering question c

From the question we are told that

The margin of error is E = 0.05

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the sample size is mathematically represented as

$n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )$

=> $n= [\frac{1.645 }}{0.05} ]^2 * 0.867 (1 - 0.867 )$

=> $n = 125 \ stores$

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3 years ago