Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
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Problem 2
<h3>Answer: True</h3>
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Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
The angle of depression is 29.0521°. So it is a safe landing.
Step-by-step explanation:
Step 1:
The plane is flying at a height of 25,000 feet and 45,000 feet away from the landing strip. Assume it lands with an angle of depression of x°.
So a right-angled triangle can be formed using these measurements. The triangle's opposite side measures 25,000 feet while the adjacent side measures 45,000 feet. The angle of the triangle is x°.
To determine the value of x, we calculate the tan of the given triangle.

Step 2:
The length of the opposite side = 25,000 feet.
The length of the adjacent side = 45,000 feet.

So x = 29.0521°. Since x < 30°, it is a safe landing.
Answer:
2 8/9
Step-by-step explanation:
Answer:
306 inches
Step-by-step explanation:
80% = 0.8
170 inches × 80% = 170 × 0.8 = 136
The truck is 80% longer than the boat. 80% of the boat is 136.
So, the boat is 170 inches + 136 inches = 306 inches.
53
when the first decimal number is 4 or below, then you leave the whole number as it is, and get rid of the decimals.