Answer:
The answer to your question is width = 6 ft; length = 24 ft
Step-by-step explanation:
Data
Area = 144 ft²
width = w
length = l
The width is 1/4 of the length
Formula
Area = width x length = w x l
Length = 4 width l = 4w
Process
1.- Substitute length in the first equation
Area = w(4w)
Simplify
Area = 4w²
2.- Solve for w
w = 
Substitution
w = 
Simplification
w = 
Result
w = 6 ft
3.- Find l
l = 4(6)
l = 24 ft
Answer:
The midpoint M is (5,7)
Step-by-step explanation:

U(8,9)
V(2,5)
m = [(8+2)/2 , (9+5)/2]
= [(10/2) , (14/2)]
= (5,7)
(Correct me if i am wrong)
Answer: The correct option is second, i.e., x>0.
Explanation:
As we know that the domain is the set of all possible inputs. If function is defined as, f(x) then all possible value of x for which the function f(x) is defined is called domain.
In a graph the domain is defined on the x axis and the range of the function is defined on y-axis.
In the given graph the function is defined from x=0 to
because for
the graph is not defined. It means for
the function is not defined.
Sicen the graph is defined for all positive values of x, therefore the domain of the function is al real number greater than 0. It can be written as x>0 and the second option is correct.
Answer:
Step-by-step explanation:
So
f(x) = -8x +11, for f(-4).
= -8(-4)+11
= 32 + 11
= 43
Answer: G and F are mutually exclusive because they cannot occur together
Step-by-step explanation:
According to the definition of mutually exclusive events,
The events which can not occur together and probability of them occurring together is 0 are known as mutually exclusive events.
The first statement gives an implication that if one happens then other happens meaning they could both still happen so it is not true.
The second statement contradict the question about being mutually exclusive events.
The third statement also is a implication that if one event occurs then other does or does not occur.
The last statement is correct one that conforms with the question and obeys the definition of mutually exclusive events.