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Fantom [35]
3 years ago
15

An experimental vehicle is able to travel 3/8 mile on 1/16 gallon of water. What is the rate at which the vehicle can travel, in

miles per gallon of water?
Mathematics
1 answer:
sattari [20]3 years ago
3 0

The rate at which the vehicle can travel is 6 miles per gallon

<em><u>Solution:</u></em>

Given that experimental vehicle is able to travel \frac{3}{8} mile on \frac{1}{16} gallon of water

To find: Rate at which the vehicle can travel, in miles per gallon of water

distance traveled in miles = \frac{3}{8} \text{ miles }

gallon of water = \frac{1}{16} \text{ gallons }

<em><u>Miles per gallon is given as:</u></em>

\text{ miles per gallon }=\frac{\text{ distance traveled in miles}}{\text{gallon of water }}

Substituting the given value we get,

\rightarrow \frac{\frac{3}{8}}{\frac{1}{16}}\\\\\rightarrow \frac{3}{8} \times \frac{16}{1}\\\\\rightarrow 3 \times 2 = 6

So the rate at which the vehicle can travel, in miles per gallon of water is 6 miles per gallon

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Answer:

875cm^2

Step-by-step explanation:

since opposite sides are equal

3x-y=2x+y

x=2y                                                      

y=x/2                                                                      ....(i)

thus new length=2x+y

=2x+(x/2)                                                              [using (i)]

=(4x+x)/2

l=5x/2                                                                   .....(ii)

now,

perimeter=2(l+b)=120cm

l+b=60cm            

from figure and using (ii)

[5x/2]+2x-3=60

[5x+4x-6]/2=60

9x-6=120

9x=126

x=126/9

x=14                                                                 ..........(iii)

substitute (iii) in (i)

y=14/2

y=7                                                                  ...........(iv)

From figure,

length=2x+y                                                   [using (iii) and (iv)]

=2x14+7

length=35cm

breadth=2x-3

=2x14-3                                                          ....[using(iii)]

=28-3

breadth=25cm

now,

Area=lxb

=35x25

=875cm^2

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3 years ago
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First correct answer will get Brainliest, 30 mins to answer! 25 points
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Answer:

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Step-by-step explanation:

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Which expression is equivalent to the following complex fraction?
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The equivalent expression of (1 + \frac{1}{y}) \div (1-\frac 1y) is \frac{y + 1}{y-1}

<h3>How to determine the equivalent fraction?</h3>

The fraction is given as:

(1 + \frac{1}{y}) \div (1-\frac 1y)

Take the LCM

\frac{y + 1}{y} \div \frac{y-1}y

Express as products

\frac{y + 1}{y} \times \frac{y}{y-1}

Evaluate the product

\frac{y + 1}{y-1}

Hence, the equivalent expression of (1 + \frac{1}{y}) \div (1-\frac 1y) is \frac{y + 1}{y-1}

Read more about equivalent expression at:

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