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3 years ago

Put the equation in standard form with a positive x coefficient y - 1 = 5/6 (x-4)

Mathematics

1 answer:

Anon25 [30]3 years ago

3 0

Answer:

5x - 6y = 14

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

given

y - 1 = $\frac{5}{6}$ (x - 4)

Multiply through by 6 to eliminate the fraction

6y - 6 = 5(x - 4) ← distribute

6y - 6 = 5x - 20 ( add 20 to both sides )

6y + 14 = 5x ( subtract 6y from both sides )

14 = 5x - 6y , thus

5x - 6y = 14 ← in standard form

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Put the equation in standard form with a positive x coefficient y - 1 = 5/6 (x-4) ​

Put the equation in standard form with a positive x coefficient y - 1 = 5/6 (x-4)