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Umnica [9.8K]
3 years ago
11

What is the domain of the function in this table ?

Mathematics
2 answers:
gayaneshka [121]3 years ago
4 0

The answer is C just because the domain is the x in an x,y pair

ankoles [38]3 years ago
4 0

Hello from MrBillDoesMath!

Answer:

Choice C

Discussion:

The domain of a function can be thought of as the set of "x" values for which it is defined. So Choice C is the correct answer. (Note that choice A is NOT the answer as it contains (x,y) pairs, not single "x" values)

Thank you,

MrB

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53 dL = ______ daL im struggling with this one<br> .
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Answer:

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Step-by-step explanation:

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3 years ago
Rico is trying to estimate 139 times 18?100 times 10=1,000
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140 x 20
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8 0
3 years ago
Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$
Viefleur [7K]

QUESTION 1

Given that:

f(x)=2x^2+3x-9,

g(x)=5x+11,

and

h(x)=-3x^2+1

Then;

f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)

f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1

Group similar terms;

f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1

Simplify;

f(x)-g(x)+h(x)=-x^2-2x-19

QUESTION 2

Given that;

f(x)=4x-7.

g(x)=(x+1)^2

and

s(x)=f(x)+g(x)

Substitute the functions;

s(x)=4x-7+(x+1)^2

Substitute x=3

s(3)=4(3)-7+(3+1)^2

s(3)=12-7+(4)^2

s(3)=5+16

s(3)=21

QUESTION 3

Given:

f(x)=3x+2

g(x)=x^2-5x-1

f(g(x))=f(x^2-5x-1)

This implies that;

f(g(x))=3(x^2-5x-1)+2

Expand the parenthesis;

f(g(x))=3x^2-15x-3+2

f(g(x))=3x^2-15x-1

QUESTION 4

The given function is;

f(x)=3(x-6)^2+1

Let

y=3(x-6)^2+1

\Rightarrow y-1=3(x-6)^2

\Rightarrow \frac{y-1}{3}=(x-6)^2

\Rightarrow \sqrt{\frac{y-1}{3}}=x-6

\Rightarrow x=6+\sqrt{\frac{y-1}{3}}

The range is:

\frac{y-1}{3}\ge0

y-1\ge0

y\ge1

The interval notation is;

[1,+\infty)

6 0
3 years ago
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timofeeve [1]
6 divided by 4(3/5)
After multiplying the fraction we get 23/5
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8 0
3 years ago
How would you write - 4.5 as a fraction
Helga [31]
You would write it as -4 1/2
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3 years ago
Read 2 more answers
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