Ask question

Ask question

All categories

3 years ago

9

fifteen out of the 60 eighth-graders at sebring junior high are on the track team. what percent of the eight-graders are on the

track team?

1 answer:

allsm [11]3 years ago

8 0

Answer:

25%

Step-by-step explanation:

You have 60 total, 30 on the track team would be 50%, but there is only 15 on the track them, you cut the 50% in half again which gives 25%.

You might be interested in

Somebody help me pleaseeeeeeeeee

Fudgin [204]

Answer:

Write the inequality: 2.90h + 4.75

Solve the inequality: 2.90h + 4.75 = 39.55

Step-by-step explanation:

I’m not really sure if its correct I got it off somebody else’s brainly account

I’m actually currently doing the test right now and ive been using you’re page for the answers, thanks you’re account was a big help .

6 0

3 years ago

What is the slope of the line 6x + y = 24?

ValentinkaMS [17]

Answer:

-6

Step-by-step explanation:

You need to get it in Point-Slope form, or

y = mx + b

Isolate y by subtracting 6x

You are left with:

y = -6x + 24

M is the slope, so in this case, it is -6

5 0

2 years ago

Read 2 more answers

Which answer choice is the best first st 2y – 6 = -1 ? pls help asap

natima [27]

Answer:

y=2.5

Step-by-step explanation:

2y-6=-1

add 6 to negative 1 so that the 2y is all by itself

2y=5

divide 5 by 2

y=2.5

4 0

3 years ago

Read 2 more answers

Each container must hold exactly 1 litre of water Each container must have a minimum surface area

Arada [10]

The containers must be spheres of radius = 6.2cm

<h3>How to minimize the surface area for the containers?</h3>

We know that the shape that minimizes the area for a fixed volume is the sphere.

Here, we want to get spheres of a volume of 1 liter. Where:

1 L = 1000 cm³

And remember that the volume of a sphere of radius R is:

$V = \frac{4}{3}*3.14*R^3$

Then we must solve:

$V = \frac{4}{3}*3.14*R^3 = 1000cm^3\\\\R =\sqrt[3]{ (1000cm^3*\frac{3}{4*3.14} )} = 6.2cm$

The containers must be spheres of radius = 6.2cm

If you want to learn more about volume:

brainly.com/question/1972490

#SPJ1

6 0

2 years ago

Tanya runs diagonally across a rectangular field that has a length of 40 yards and a width of 30 yards. How far did Tanya run?

Yuliya22 [10]

Tanya run 50 yards across the diagonal of the rectangular field.

<u>Step-by-step explanation</u>:

Step 1 :

Length of the rectangular field = 40 yards
width of the rectangular field = 30 yards

Step 2 :

Measure of the diagonal = √(length^2 + width^2 )

Step 3 :

Diagonal = √(40^2 + 30^2 )

= √(1600 + 900)

= √2500

= ±50

Step 4 :

Since distance cannot be negative, The measure of diagonal = 50 yards.

∴ Tanya runs diagonally across a rectangular field is 50 yards.

4 0

3 years ago