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Svetradugi [14.3K]
2 years ago
10

Do the ratios 6/1 and 18/3 forma proportion yes or no?

Mathematics
1 answer:
andrezito [222]2 years ago
4 0
I'm pretty sure it's no...
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x = -10

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The school water fountain can only fill 3/4 of a jug at a time. With this amount of water, Mr. Kern can water 3/8 of his plants.
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36m⁴-√16 pls help asap​
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Answer:

Step-by-step explanation:

(a^2-b^2)=(a-b)(a+b)\\ \\ 36m^4-4\\ \\ (6m^2-2)(6m^2+2)\\ \\ 4(3m^2-1)(3m^2+1)

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3 years ago
Help! If you know this can you tell me how to do it?
aleksandr82 [10.1K]

Answer:

c

Step-by-step explanation:

Here's how this works:

Get everything together into one fraction by finding the LCD and doing the math.  The LCD is sin(x) cos(x).  Multiplying that in to each term looks like this:

[sin(x)cos(x)]\frac{sin(x)}{cos(x)}+[sin(x)cos(x)]\frac{cos(x)}{sin(x)} =?

In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:

\frac{sin^2(x)}{sin(x)cos(x)}+\frac{cos^2(x)}{sin(x)cos(x)}=?

Put everything over the common denominator now:

\frac{sin^2(x)+cos^2(x)}{sin(x)cos(x)}=?

Since sin^2(x)+cos^2(x)=1, we will make that substitution:

\frac{1}{sin(x)cos(x)}

We could separate that fraction into 2:

\frac{1}{sin(x)}×\frac{1}{cos(x)}

\frac{1}{sin(x)}=csc(x)  and  \frac{1}{cos(x)}=sec(x)

Therefore, the simplification is

sec(x)csc(x)

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3 years ago
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