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Svetradugi [14.3K]
3 years ago
10

Do the ratios 6/1 and 18/3 forma proportion yes or no?

Mathematics
1 answer:
andrezito [222]3 years ago
4 0
I'm pretty sure it's no...
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Please helpppppppppp
Alika [10]

Answer:

x = 1/3

Step-by-step explanation:

f(x) = -3x^2 + 2x-17

This is in the form

ax^2 +bx+c

a = -3  b = 2  c = -17

The axis of symmetry is at

x = -b/2a

x = -2/ (2*-3)

x = -2/-6

x = 1/3

8 0
3 years ago
Write a related subtraction fact for 9+3=12. Explain how the two facts are related
postnew [5]
12-3=9 they switch up and it still equals the same thing
5 0
3 years ago
Read 2 more answers
You are in $33 in eight hours at that rate how much would you earn in five hours
svp [43]

Answer:

20.625 dollars or about 20.63 dollars

Step-by-step explanation:

33/8 = 4.125

4.125 times 5 = 20.625

4 0
3 years ago
Point A is located at (−2, −6), and D is located at (−6, 8). Find the coordinates of the point that lies halfway between A and D
Afina-wow [57]

Answer:

(-4,1)

Step-by-step explanation:

Point A is located at (−2, −6), and D is located at (−6, 8).

We need to find the midpoint of A  and D

Mid point formula is (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Point A is (-2,-6) that is (x1,y1)

Point D is (-6,8) that is (x2, y2)

plug in the values in the formula

(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

(\frac{-2-6}{2}, \frac{-6+8}{2})

(\frac{-8}{2}, \frac{2}{2})

Mid point is (-4, 1)

5 0
3 years ago
Read 2 more answers
What is the cross-sectional area of a wire if its outside diameter is 0.0625 inch?
Leno4ka [110]

Given that the diameter: d= 0.0625 inch.

So, radius of the wire : r = \frac{0.0625}{2} = 0.03125 inch

Now the formula to find the cross-sectional area of wire ( circle) is:

A = πr²

= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125

=3.14 * 0.000976563

= 0.003066406

= 0.00307 (Rounded to 5 decimal places).

Hence, cross-sectional area of a wire is 0.00307 square inches.

Hope this helps you!

5 0
3 years ago
Read 2 more answers
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